8g of a metal hydroxide on heating produces 5g of metal oxide. If the atomic mass of the metal is 7, the formula of its chloride is ?

$M C l_{3}$

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$M C l_{2}$

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$M C l$

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$N o n e o f t h e s e$

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Solution

The correct option is C
$M C l$

$\frac{M a s s o f h y d r o x i d e}{E q u i v . m a s s o f h y d r o x i d e} = \frac{M a s s o f o x i d e}{E q u i v . m a s s o f o x i d e}$
or $\frac{8}{E_{M} + E_{E_{O H^{-}}}} (= \frac{8}{E_{M} + 17})$
$= \frac{5}{E_{M} + E_{O}} (= \frac{5}{E_{M} + 8}) \Rightarrow E_{M} = 7$
$V a l e n c y = \frac{A t o m i c m a s s}{E q u i v . m a s s} = \frac{7}{7} = 1;$
Hence metal chloride = MCl

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8g of a metal hydroxide on heating produces 5g of metal oxide. If the atomic mass of the metal is 7, the formula of its chloride is ?

The correct option is C MCl Mass of hydroxideEquiv.mass of hydroxide=Mass of oxideEquiv.mass of oxide or 8EM+EEOH−(=8EM+17) =5EM+EO(=5EM+8)⇒EM=7 Valency=Atomic massEquiv.mass=77=1; Hence metal chloride = MCl