9.0 g water is added into oleum sample labelled as 1127%H2SO4. The volume of free SO3 remaining in the solution is :
A
14.93 L at STP
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B
7.46 L at STP
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C
3.73 L at STP
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D
11.2 L at STP
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Solution
The correct option is D3.73 L at STP The oleum sample is labelled as 112%H2SO4.
9 g water is added. Hence, 12−9=3 g water is yet to be added. This corresponds to 318=0.167 mol water to be added. This corresponds to 0.167 moles of free SO3 which occupies a volume of 22.4×0.167=3.73 L at STP.