The correct option is D 101 ppm
Equivalents of CaCO3= Equivalents of MgCl2+ Equivalents of CaSO4
WCaCO3100×2=0.009595×2+0.000136136×2WCaCO3=(1×10−4+1×10−6)×100
∴ WCaCO3≈0.0101 g
WH2O=100 g
Hardness=Mass of CaCO3Mass of hard water×106 ppm
∴ Hardness=0.0101100×106 ppm
Hardness=101 ppm