9 2 A -9 tan 2 A is equal toA- 1B- 9C- 8D- 0

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Trigonometric Identities

9 2 A -9 tan ...

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$9 s e c^{2} A - 9 t a n^{2} A$ is equal to

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9 s e c^{2} A - 9 t a n^{2} A =

9 s e c^{2} A - 9 t a n^{2} A =

9 {sec}^{2} A - 9 {tan}^{2} A = . . . . . . . . . .

Choose the correct option. Justify your choice.

(i) $9 {sec}^{2} A - 9 {tan}^{2} A =$

(A) $1$

(B) $9$

(D) $0$

(ii) $(1 + tan θ + sec θ) (1 + cot θ - cosec θ)$

(A) $0$

(B) $1$

(D) $- 1$

(iii) $(sec A + tan A) (1 - sin A) =$

(A) $sec A$

(B) $sin A$

(D) $cos A$

(iv) $\frac{1 + {tan}^{2} A}{1 + {cot}^{2} A} =$

(A) ${sec}^{2} A$

(B) $- 1$

(D) ${tan}^{2} A$

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