Question

${}_{92}^{235}U$ nucleus absorbs a neutron and disintegrates into ${}_{54}^{139}X$, ${}_{38}^{94}Sr$ and '$x$'. What will be the product $x$?

• A. $3$-neutrons
• B. $2$-neutrons
• C. $\alpha$-particles
• D. $\beta$-particles

Answer 1

Answer: (B)

$2$-neutrons

${}_{92}^{235}U+1n⟶{}_{54}^{139}Xe{+}_{38}^{94}Sr+xn.$

$\Rightarrow 235+1=139+194+x$

$\Rightarrow x=3$

$\therefore$The product x is 3 neutrons.