Question

${}_{92}{U}^{235}$ nucleus absorbs a neutron and disintegrate in ${}_{54}{Xe}^{139}$, ${}_{38}{Sr}^{94}$ and $X$ so, what will be product $X$?

• A. $3$-neutrons
• B. $2$-neutrons
• C. $\alpha$-particle
• D. $\beta$-particle

Answer 1

Answer: (A)

$3$-neutrons

${}_{92}{U}^{235}$ nucleus absorbs a neutron and then disintegrate into ${}_{54}{Xe}^{139}$, ${}_{38}{Sr}^{94}$ and $X$.

Thus,

${}_{92}{U}^{235}{+}_0{n}^1{⟶}_{54}{Xe}^{139}{+}_{38}{Sr}^{94}+3_0{n}^1$

Hence, option A is correct.