Question

${}_{92}{U}^{235}$ nucleus absorbs a slow neutron and undergoes fission into${}_{54}{Xe}^{139}$ and ${}_{38}{Sr}^{94}$ nuclei. The other particles produced in this fission process are

• A. $1\beta$ and $1\alpha$
• B. $2\beta$ and $1neutron$
• C. $2neutrons$
• D. $3neutrons$

Answer 1

The correct option is D $3neutrons$

$\begin{array}{c}\text{* From this reaction we conclude that -}\\ \text{- we get no change in total atomic number of}\\ \text{the products from the reactant nuclei.}\\ \text{- we get a change of 3 units in atomic masses}\\ \text{of products less than the Reactant.}\\ \text{Then,we can say that emission of neutrons}\\ \text{is one of the possible ways .}\\ \text{Hence, option (d) is correct.}\end{array}$