You visited us 8 times! Enjoying our articles? Unlock Full Access!

Oxidation Number Method

9Fe2O3+2NH3 →...

Question

$9 F e_{2} O_{3} + 2 N H_{3} \to 6 F e_{3} O_{4} + N_{2} + 3 H_{2} O$
According to the balanced equation above , when 1 mole of $N H_{3}$ reacts completely, which of the following is true?

1 mole of

N_{2}

must be formed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 mole of

H_{2} O

must be formed

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 mole of

F e_{3} O_{4}

must be formed

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 mole of

F e_{2} O_{3}

must be react

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 mole of

F e_{2} O_{3}

must be react

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 3 mole of $F e_{3} O_{4}$ must be formed
According to equation 2 moles of $N H_{3}$ react to give 6 moles of ${F e}_{3} O_{4}$ .
Ratio of $N H_{3}$ : ${F e}_{3} O_{4}$ is 1:3.
Hence, 1 mole of $N H_{3}$ react to give 3 moles of ${F e}_{3} O_{4}$ .

Suggest Corrections

Similar questions

B_{2} O_{3} + M g \to M g O + B

B_{2} O_{3}

S_{2} O_{8}^{2 -} + I^{-} S O_{4}^{2 -} + I_{2}

N a_{2} S_{2} O_{8}

6

C u (s) + H N O_{3} (a q) \to C u (N O_{3})_{2} (a q) + H_{2} O (l) + N O (g)

N H_{4} C l

N H_{3}

C l_{2}

N H_{3} + C l_{2} \to N_{2} + N H_{4} C l

1

Join BYJU'S Learning Program