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Oxidation Number Method

9Fe2O3+2NH3 →...

Question

$9 F e_{2} O_{3} + 2 N H_{3} \to 6 F e_{3} O_{4} + N_{2} + 3 H_{2} O$
According to the balanced equation above , when 1 mole of $N H_{3}$ reacts completely, which of the following is true?

1 mole of

N_{2}

must be formed

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1 mole of

H_{2} O

must be formed

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3 mole of

F e_{3} O_{4}

must be formed

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2 mole of

F e_{2} O_{3}

must be react

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4 mole of

F e_{2} O_{3}

must be react

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Solution

The correct option is B 3 mole of $F e_{3} O_{4}$ must be formed
According to equation 2 moles of $N H_{3}$ react to give 6 moles of ${F e}_{3} O_{4}$ .
Ratio of $N H_{3}$ : ${F e}_{3} O_{4}$ is 1:3.
Hence, 1 mole of $N H_{3}$ react to give 3 moles of ${F e}_{3} O_{4}$ .

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