9th term of the expansion 4x- 12x12is

T9= nbsp;C812 nbsp;(4x)12 nbsp; nbsp;8 nbsp; nbsp;( 12x)8= nbsp;C812 nbsp;(4x)4 nbsp;(12)8 nbsp; nbsp;(1x)4= nbsp;C812 ...

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General Term of Binomial Expansion

9th term of t...

Question

9th term of the expansion $(4 x - \frac{1}{2 \sqrt{x}})^{12}$ is

12 C 6

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12 C 7

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12 C 8

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12 C 10

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