$9 x^{4} - 40 x^{2} + 16$ can be factorised as

(x + 1) (x - 1) (2 x + 1) (2 x - 1)

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(2 x - 1) (4 x^{2} + 2 x + 1)

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(x + 2) (2 x - 3) (x - 1) (2 x + 3)

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None of these

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Solution

The correct option is D None of these
$9 x^{4} - 40 x^{2} + 16 = 9 x^{4} - 36 x^{2} - 4 x^{2} + 16$
$= 9 x^{2} (x^{2} - 4) - 4 (x^{2} - 4)$
$= (x^{2} - 4) (9 x^{2} - 4)$
$= (x + 2) (x - 2) (3 x + 2) (3 x - 2)$

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