Circuit Theory

Q. In the figure given below the value of R is

1. 2.5 $\Omega$
2. 5.0 $\Omega$
3. 7.5 $\Omega$
4. 10.0 $\Omega$

Q.

Can you use superposition with dependent sources?

Q.

Three resistors are connected to a $12V$ battery as shown in the figure given below :

1. What is current through $8\mathrm{ohm}$ resistor?
2. What is the potential difference across the parallel combination of $6\mathrm{\Omega }$ and $12\mathrm{\Omega }$ resistor?
3. What is the current through $6\mathrm{\Omega }$ resistor?

Q.

In the circuit shown, the current through $ 8 \Omega $ is same before and after connecting $ E$. The value of $ E$ is

Q.

In a given circuit inductor of $ \mathrm{L} = 1\mathrm{mH}$ and resistance $ \mathrm{R} = 1\mathrm{\Omega }$ are connected in series to ends of two parallel conducting rods as shown. Now a rod of length $ 10 \mathrm{cm}$ is moved with constant velocity of 1 cm/s in magnetic field $ \mathrm{B} = 1\mathrm{T}.$ If rod starts moving at $ \mathrm{t} = 0$ then current in circuit after 1 millisecond is $ \mathrm{x} . {10}^{-3 }\mathrm{A}.$ Then the value of$ \mathrm{x} $is: (given $ {\mathrm{e}}^{-1} = 0.37$)

Q. If the band stop filters is to reject a 200 Hz Sinusoid, while passing other frequencies calculate the values of L and C. Take $R=150\Omega$ and bandwidth as 100 Hz.

1. $0.5H,2.66\mu F$
2. $0.2387mH,2.66F$
3. $0.2387H,2.66F$
4. $0.2387H,2.66\mu F$

Q. A fully charged mobile phone with a 12 V battery is good for a 10 minutes talk-time. Assume that, during the talk-time the battery delivers a constant current of 2 A and its voltage drops linearly from 12 V to 10 V as shown in the figure. How much energy does the battery during this talk-time?

1. 220 J
2. 12 kJ
3. 13.2 kJ
4. 14.4 J

Q. In the circuit shown below, the current through the inductor is

1. $\frac{2}{1+j}A$
2. $\frac{-1}{1+j}A$
3. $\frac{1}{1+j}A$
4. 0 A

Q.

Consider the network shown below with $R_1=1\Omega$, $R_2=2\Omega$ and $R_3=3\Omega$. The network is connected to a constant voltage source of 11 V.


The magnitude of the current (in amperes, accurate to two decimal places) through the sources is

1. 8

Q. Consider the following figure:


The current $I_s$ in Amps in the voltage source, and voltage $V_s$ in volts across the current source respectively, are

1. 13, -20
2. 8, -10
3. -8, 20
4. -13, 20