Congruent Triangles
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My attempt -
Angle A + Angle B = 105° ..... (1)
Angle B + Angle C = 120°
or Angle C = 120° – Angle B ........ (2)
Now, Angle A + Angle B + Angle C = 180° (Angle Sum property of a triangle)
or 105° + 120° - Angle B = 180° (Substituting values from (1) and (2))
or 225° - Angle B = 180°
or Angle B = 225° – 180° = 45°
I am doubtful of my solution. Can you please help me determine if I've solved it the correct way? I know it's a simple question, still silly doubts. Thanks!
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20o, 60o, 80o
40o, 60o, 80o
80o, 40o, 60o
In a triangle ABC, angle A- angle B=33degree and angle B- angle C=18 degree, then the measure of angle B is?
In figure, QA and PB are perpendicular to AB. If AO = 10cm, BO = 6cm and PB = 9cm.
Find AQ.
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AEF
AFE, BFD, CDE
ABC
BFD, CDE
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40o, 60o, 80o
70o, 46o, 64o
80o, 50o, 50o
60o, 90o, 30o
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50∘
60∘
70∘
80∘
If ΔPQR≅ ΔEFD, then ED=
PQ
QR
None of these
PR
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DE = 5 cm, ∠D=40∘
DE = 5 cm, ∠E=60∘
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LK
KM
LM
None of these
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- False
- True
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AC = PR
AB = PQ
QR = BC
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∠A, BC
∠B, AB
∠C, AB
Both ∠C and ∠A, BC
The angles of a triangle are in the ratio 1:2:3, find the measure of each angle of the triangle
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AB = BC
AB = AC
AC = BC
None of these