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Question

D, E, F are the mid-point of the sides BC, CA and AB respectively of ΔABC, then ΔDEF is congruent to triangle



A

ABC

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B

AEF

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C

BFD, CDE

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D

AFE, BFD, CDE

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Solution

The correct option is B

AFE, BFD, CDE


In ΔABC,D,E,F are the mid-points of the sides BC, CA, AB respectively DE, EF and FD are joined

 E and F ar the mid-points AC and AB.

 EF=12BC and EF || BC

Similarly, DE=12AB and DE || AB

DF=12 AC and DF || AC

 ΔDEF is congruent toΔAFE, ΔBFD, ΔCDE


Mathematics
RD Sharma
Standard IX

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