Converse of Theorem 2
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In the given figure, ABCD is a quadrilateral. A line through 'D', parallel to AC, meets BC produced in P. Then:
- Area (Δ ABP) = Area (quad ABCD)
- Area (ΔABC) = Area (ΔACP)
- None of the above
- Area (ΔBCD) = Area (quad ACPD)
- AB⊥ CD
- AB ∥ CD
- AB = CD
- AB ≠ CD
- Square
- Rectangle
- Trapezium
- Rhombus
In the given figure, ABCD is a quadrilateral. A line through 'D', parallel to AC, meets BC produced in P. Then:
- Area (Δ ABP) = Area (quad ABCD)
- Area (ΔABC) = Area (ΔACP)
- Area (ΔBCD) = Area (quad ACPD)
- None of the above
- True
- False
The line drawn through the centre of a circle to bisect a chord is
If AB is a chord of a circle with center O, and AC=BC, then x=90∘.
80°
90°
In the figure, O is the centre of the circle of radius 5 cm. P and Q are points on chords AB and CD respectively such that OP⊥AB, OQ⊥CD, AB||CD, AB=6 cm and CD=8 cm. Determine PQ.
8 cm
5 cm
6 cm
7 cm
O is the centre of the circle of radius 5 cm, OP is perpendicular to AB, OQ is perpendicular to CD, AB||CD, AB=6 cm and CD=8 cm. Determine PQ.
3cm
4cm
1cm
2cm
If each of two chords, AB and CD, of a circle are at a distance of 4 cm from the centre, then AB=CD.
True
False