Method of Elimination
Trending Questions
A fraction becomes 45 if one is added to both numerator and denominator. If, however, 5 is subtracted from numerator and denominator, the resultant fraction becomes 12. Find the fraction.
−79
710
−710
79
- 25
- 24
- 43
- 42
- 5, 3
- 7, 4
- 9, 6
- 10, 7
The sum of a two digit number and the number obtained by reversing the digits is 121 and the two digits differ by 3. Find the number.
62 or 26
47 or 74
41 or 14
87 or 87
The sum of digits of a two-digit number is 13. If the number is subtracted from the one obtained by reversing the digits, the result is 45. Find the number.
- 94
- 49
- 85
- 76
Write an equation of a line passing through the point representing solution of the pair of linear equations x + y = 2 and 2x – y = 1, how many such lines can we find?
√3x−√2y=√3;√5x+√3y=√2
The sum of two numbers is 209. If one number is 7 less than two times of the other, then find the two numbers.
137 and 72
133 and 74
147 and 62
127 and 82
Find the solution of the given system of equations.
x+y−82=x+2y−148=3x+y−1211
(1, -1)
(2, 6)
(2, 2)
(0, 1)
- 3x−2y+4=0
- 2x−3y−4=0
- 3x−2y−4=0
- 2x−3y+4=0
Question 39
State whether the following statement is true (T) or false (F).
Two different equations can never have the same answer.
Solve the two equations using method of elimination.
a1x+b1y+c1=0
a2x+b2y+c2=0
x = (b1c2−b2c1)(a1b2−a2b1), y = (c1a2−c2a1)(a1b2−a2b1)
x = (b2c1−b1c2)(a1b2−a2b1), y = (c1a1−c2a2)(a1b2−a2b1)
x = (b2c2−b1c1)(a1b2−a2b1), y = (c2a2−c1a1)(a1b2−a2b1)
x = (b1c2+b2c1)(a1b2+a2b1), y = (c1a2+c2a1)(a1b2+a2b1)
131x+217y=827.
From Bangalore bus stand, if we buy 2 tickets to Malleshwaram and 3 tickets to Yeshwanthpur, the total cost is ₹ 46; but if we buy 3 tickets to Malleshwaram and 5 tickets to Yeshwanthpur, then the total cost is ₹ 74. Find the fares from Bangalore bus stand to Malleshwaram and to Yeshwanthpur respectively.
₹12 and ₹ 10
₹ 10 and ₹ 8
₹ 10 and ₹ 12
₹ 8 and ₹ 10
The sum of the digits of a two-digit number is 9. If 27 is added to it, the digits are reversed. Find the number.
27
63
36
72
3x–4y=1 ---------- (1)
5x–6y=7 ---------- (2)
In the above equations, what operation should be carried out to make the coefficients of x equal?
- Multiply equation (1) by 6 and equation (2) by 4
- Multiply equation (1) by 3 and equation (2) by 5
- Multiply equation (1) by 5 and equation (2) by 3
- Multiply equation (1) by 8 and equation (2) by 3
Solve
13x + 11y = 70
11x + 13y = 74
x = 2 and y = 4
x = -2 and y = -4
x = 2 and y = 6
x = 3 and y = 4
(i) p(x)=2x3+x2−2x−1, g(x)=x+1
(ii) p(x)=x3+3x2+3x+1, g(x)=x+2
(iii) p(x)=x3−4x2+x+6, g(x)=x−3
The sum of a two digit number and the number formed by interchanging the digits is 132. If 12 is added to the number, the new number becomes 5 times the sum of the digits. Find the number.
132
39
48
88
Find the solution of the given pair of equations
2x+3y=9, 3x+4y=5
- x = 21, y = 7
- x = - 21, y = 17
- x = 19, y = 14
- x = 20, y = 12
x + 2y = 5 and 4x + 4y - 6 = 0 are equations of two lines which intersect at (−3, 53)
True
False
3x–4y=1...(1)
5x–6y=7...(2)
In the above equations, which of the following step can to be done to numerically equate the coefficients of x?
Multiply equation (1) by 3 and equation (2) by 5.
Multiply equation (1) by 6 and equation (2) by 4.
Multiply equation (1) by 5 and equation (2) by 3.
Multiply equation (1) by 4 and equation (2) by 6.
5x−2y=10 and 4x−6y=3
- −2711 and 2522
- 2711 and −2522
- 2711 and 2522
- −2711 and −2522
- x=195, y=65
- x=247, y=65
- x=132, y=65
- x=177, y=65
If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then find the smallest even number.
4
6
8
2
If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then the difference between the sum of 5 consecutive odd numbers and 4 consecutive even numbers is
1
3
7
5
If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178 and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then find the middle number when all the numbers are arranged in ascending order.
9
8
7
6
If twice the sum of 5 consecutive odd numbers and thrice the sum of 4 consecutive even numbers is 178. and thrice the sum of 5 consecutive odd numbers and twice the sum of 4 consecutive even numbers is 177, then if all the 9 numbers are arranged in ascending order , the sum of the smallest and largest number is
15
16
18
17