Two Triangles Having the Same Base & Equal Areas
Trending Questions
Q. Question 1
The median of a triangle divides it into two:
A) Triangle of equal area
B) Congruent triangles
C) Right angle triangles
D) Isosceles triangle
The median of a triangle divides it into two:
A) Triangle of equal area
B) Congruent triangles
C) Right angle triangles
D) Isosceles triangle
Q.
Show that a median of a triangle divides it into two triangles of equal areas.
Q.
The base of a parallelogram is thrice its height. If the area is 867 sq. cm, find the base of the parallelogram.
34 cm
51 cm
17 cm
68 cm
Q. XY is a line parallel to side BC of a triangle ABC. If BE||AC and CF||AB meet XY at E and F respectively,
show that ar(ΔABE)=ar(ΔACF)
show that ar(ΔABE)=ar(ΔACF)
Q. Question 7
D and E are points on sides AB and AC respectively of ΔABC such that ar (DBC) = ar (EBC). Prove that DE || BC.
D and E are points on sides AB and AC respectively of ΔABC such that ar (DBC) = ar (EBC). Prove that DE || BC.
Q.
Given a triangle ABC and E is mid point of median AD of ∆ABC. If ar(∆BED) = 20 cm2, then ar(∆ABC) is:
10 cm2
5 cm2
60 cm2
80 cm2
Q.
If the base of a parallelogram is 8 cm and its altitude is 5 cm, then its area is equal to
15 cm2
20 cm2
40 cm2
10 cm2
Q. Question 11 (v)
In ΔABC and ΔDEF , AB=DE, AB || DE, BC =EF and BC ⃦EF. Vertices A, B and C are joined to vertices D, E and F respectively ( see the given figure). Show that AC = DF .
In ΔABC and ΔDEF , AB=DE, AB || DE, BC =EF and BC ⃦EF. Vertices A, B and C are joined to vertices D, E and F respectively ( see the given figure). Show that AC = DF .
Q. The area of parallelogram of altitude 12cm is 108cm.square.Find the base of parallelogram
Q.
Area of a parallelogram is equal to