Center of Mass as an Average Point
Trending Questions
- a2(i+1√3)
- a2(3i+5j)
- a2(3i+j)
- a2(3i+j/√3)
A uniform rod of length l=100 cm is bent at its mid-point to make 90∘ angle. The distance of the centre of mass from the centre of the rod is
36.1 cm
25.2 cm
Zero
17.7 cm
Where is the Center of Mass of the 3 particle system shown in above figure?
- None of these
- Xcm=1.07Ycm=1.33
- Xcm=1.5Ycm=1.6
- Xcm=1.15Ycm=1.5
- 76 kg
- 85 kg
- 92 kg
- 80.5 kg
- at a fixed distance from one of the pucks
- usually , but not always , between the two pucks.
- at a distance from one of the pucks that is a fixed ratio to the distance between the two pucks.
- sometimes closer to one puck and sometimes closer to the other.
Three particles each of mass m, are placed at the corners of an equilateral triangle of side a, as shown in the figure. The position vector of the centre of mass is
a2(^i+^j√3)
a2(3^i+^j)
a2(3^i+√3^j)
a2(3^i+^j√3)
Four particles, each of mass m, are placed at the corners of a square of side a as shown in the figure. The position vector of the centre of mass is
a(^i+^j)
a2(^i+^j)
a(^i−^j)
a2(^i−^j)
नीचे दिए गए प्रश्न के लिए अनुच्छेद
A bob of mass m connected to string of length l, is released from rest when the string is horizontal.
l लम्बाई की डोरी से संयोजित m द्रव्यमान के एक गोलक को विराम से छोड़ा जाता है, जब डोरी क्षैतिज है।
Q. Tension in the string at angular position θ is
प्रश्न - कोणीय स्थिति θ पर डोरी में तनाव है
- 3mg cosθ
- 2mg cosθ
- mgcosθ
- 2mg sinθ
- At any point on the surface.
- At the Geometric Center
- Closer to the more Massive End.
- Closer to the least Massive End.
Four particles of masses m, m, 2m and 2m are placed at the four corners of a square of side a as shown in the figure. The (x, y) coordinates of the centre of mass are
(a2, 2a)
(a2, a)
(a, a3)
(a2, 2a3)
One end of a thin uniform rod of length L and mass M1 is rivetted to the centre of a uniform circular disc of radius r and mass M2, so that both are coplanar. The distance of centre of mass of the combination from the centre of the disc is
L(M1+M2)2M1
LM12(M1+M2)
2(M1+M2)LM1
2LM1(M1+M2)
Four particles of masses m, m, 2m and 2m are placed at the four corners of a square of side a as shown in the figure. The (x, y) coordinates of the centre of mass are
(a2, a)
(a2, 2a)
(a, a3)
(a2, 2a3)
In HCl molecule, the separation between the nuclei of hydrogen and chlorine atoms is 1.27 ∘A. If the mass of a chlorine atom is 35.5 times that of a hydrogen atom, the centre of mass of the HCl molecule is at a distance of
35.5×1.2736.5∘A from the hydrogen atom.
35.5×1.2736.5∘A from the chlorine atom.
1.2736.5∘A from the hydrogen atom.
1.2736.5∘A from the chlorine atom.
One end of a thin uniform rod of length L and mass M1 is rivetted to the centre of a uniform circular disc of radius r and mass M2, so that both are coplanar. The distance of centre of mass of the combination from the centre of the disc is
L(M1+M2)2M1
2(M1+M2)LM1
LM12(M1+M2)
2LM1(M1+M2)
Three particles, each of mass m, are placed at the corners of a right-angled triangle as shown in the figure. If OA = a and OB = b, the position vector of the centre of mass is
13(a^i−b^j)
23(a^i−b^j)
23(a^i+b^j)
13(a^i+b^j)
Three particles each of mass m, are placed at the corners of an equilateral triangle of side a, as shown in the figure. The position vector of the centre of mass is
a2(^i+^j√3)
a2(3^i+^j)
a2(3^i+√3^j)
a2(3^i+^j√3)
Three particles, each of mass m, are placed at the corners of a right-angled triangle as shown in the figure. If OA = a and OB = b, the position vector of the centre of mass is
13(a^i+b^j)
13(a^i−b^j)
23(a^i+b^j)
23(a^i−b^j)
- He stays in the same position.
- He moves towards right.
- He moves towards left.
- Insufficient information