Image Formation by Convex Lens
Trending Questions
Where should an object be placed in front of a convex lens to get a real image of the size of the object?
(a) At the principal focus of the lens
(b) At twice the focal length
(c) At infinity
(d) Between the optical centre of the lens and its principal focus
A convex lens can form
real image only
virtual image only
both real and virtual image
erect image only
The image of an object in front of a lens is larger than the object. This implies that the lens is
plane
concave
convex
can't be determined
A lens forms an enlarged, upright image of an object. What lens did you use? Also, is the image real or virual?
Concave lens. Real image.
Concave lens. Virtual image.
Convex lens. Virtual image.
Convex lens. Real image.
When is the image formed by convex lens virtual and erect?
When the object is placed between the focus F1 and optical centre O.
When the object is placed at the focus F1.
When the object is placed between the focus F1 and 2F1
When the object is placed at the focus 2F1.
In the given figure, where do the diverging rays seem to meet?
(F1 , F2 are the primary focus of the lens)
2F2
F1
F2
2F1
If there is a convex lens which is made of a material whose optical density is less than that of air, then
it remains a converging lens
it becomes a diverging lens
it doesn't refract light
it reflects the light
- opposite side of object
- Enlarge
- Real and Inverted
- Virtual and Erect
- True
- False
Imagine if there is a convex lens which is made of a material whose optical density is less than that of the air, it would still be a converging lens.
True
False
- Same size, real and inverted
- Same size, real and upright
- magnified, virtual and upright
- Diminishes, real and inverted
Find the angle between the emergent ray and incident ray when the light goes from air to glass slab. Given μglass = 1.5
- 180∘
- 0∘
- 60∘
- 30∘
- i + e = 90
- i = 2e
- i - e = 0
- i = 0.5e
Identify the condition in which image formed is real, inverted and diminished from the following.
Concave lens, object placed between focus and optical centre
Concave mirror, object placed between centre of curvature and focus
Convex lens, object placed beyond 2F1
Convex lens, object placed between F1 and 2F1
- away from the lens
- towards the lens
- first away and then towards the lens
- none of these
If F1 and F2 represents the foci of the lens, then at which point will the light rays meet?
F2
2F2
2F1
F1
Identify the condition in which image formed is real, inverted and diminished from the following.
Convex lens, object placed beyond 2F1
Concave mirror, object placed between centre of curvature and focus
Concave lens, object placed between focus and optical centre
Convex lens, object placed between F1 and 2F1
If F1 and F2 represents the foci of the lens, then at which point will the light rays meet?
2F2
F2
F1
2F1
In the given figure, where do the diverging rays seem to meet?
(F1 , F2 are the primary focus of the lens)
2F1
2F2
F2
F1
Find the angle between the emergent ray and incident ray when the light goes from air to glass slab. Given μglass = 1.5
- 0∘
- 180∘
- 30∘
- 60∘
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Assertion is incorrect but Reason is correct
Identify the condition in which image formed is real, inverted and diminished from the following.
Convex lens, object placed beyond 2F1
Convex lens, object placed between F1 and 2F1
Concave mirror, object placed between centre of curvature and focus
Concave lens, object placed between focus and optical centre
- i + e = 90
- i - e = 0
- i = 2e
- i = 0.5e
- i + e = 90
- i = 2e
- i - e = 0
- i = 0.5e
- real, inverted and magnified
- virtual, inverted and magnified
- virtual, erect and magnified
- virtual, erect and diminished
- i - e = 0
- i = 0.5e
- i = 2e
- i + e = 90