Mirror Formula and Magnification
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Mirror magnification formula
Relate the image distance (v), object distance (u) , image height (h′) and object height (h) to the formula of magnification (M) for a mirror.
M=hh′ = vu
M=h′h = −uv
M=h′h = −vu
M=h′h = uv
An object 5 cm high is placed at a distance of 60 cm in front of a concave mirror of focal length 10 cm. Find (i) the position and (ii) size, of the image.
An object of height 7 cm is kept at a distance of 25 CM in front of a concave mirror . The focal length of the mirror is 15 cm. At what distance from the mirror should a screen be kept so as to get a clear image? What will be the size and nature of image
An object is placed at 4 cm distance in front of a concave mirror of radius of curvature 24 cm. Find the position of image. Is the image magnified ?
- 1.5
- 1
- 2
- 2.5
A point light source is kept in front of a convex mirror at a distance of 40 cm. The focul length of the mirror is 40 cm. Find the position of image.
The erect image formed by a concave mirror is of size double the size of object. How are u and v related ?
The image formed by a convex mirror is of size one-third the size of object. How are u and v related ?
A convergent beam is incident on concave mirror, what will be the nature of image?
- Real and erect
- Virtual and erect
- Real and inverted
- Virtual and inverted
the position and the size?
Consider the situatuion shown in figure. A plane mirror is fixed at a height h above the bottom of a beaker containing water (refractive index μ ) up to a height d. Find the position of the image of the bottom formed by the mirror.
h−d+dμ.
h+d+dμ.
h−d−dμ.
d+dμ.
If object is placed at 60 cm before the concave mirror. The object moves with velocity 20 cm/sec towards the mirror. The magnification is -1/2 at initial position. And if magnification after 1 sec is – 1 find out the average velocity of the image for above 1 sec period.
10 cm/sec
20 cm/sec
15 cm/sec
5 cm/sec
- 15 cm
- 10 cm
- 20 cm
- 5 cm
- f=1+mmu
- f=mu
- None of these
- f=mu1+m
(a) the focal length of the mirror(b) position of image.
- 20 cm
- 22.5 cm
- 24 cm
- 30.4 cm
- 0.5 cm
- 0.66 cm
- 0.33 cm
- 1 cm
The magnification in a spherical mirror is:
Negative of the ratio of image height to the object height
Negative of the ratio of the image distance to the object distance
The ratio of image distance to the object distance
Negative of the ratio of the object distance to the image distance
- |u1+u2|
- |u1−u2|
- |u1+u22|
- |u1−u22|
- negative
- undefined
- zero
- positive
- undefined
- zero
- positive
- negative
- 1
- 2
- 3
- 4
- −4 cm
- 8 cm
- 6 cm
- 12 cm