Newton's second law
Trending Questions
The distance travelled by a moving body is directly proportional to time. Is any external force acting on it?
A car moving with a velocity of can be stopped by the application of constant force in a distance of . If the velocity of the car is , it can be stopped by this force in
- 4 m s−1
- 8 m s−1
- 32 m s−1
- 16 m s−1
A car is moving with a uniform velocity of 30 m s−1. It is stopped in 2 s by applying a force of 1500 N through its brakes. Calculate:
(a) the change in momentum of car,
(b) the retardation produced in car and
(c) the mass of the car.
What relation between force and momentum can be used to solve this problem?
"An object of mass 100 Kg is accelerated uniformly from a velocity of 5 m/s to 8 m/s in 6 seconds. Calculate the initial and final momentum of the object. Also, find the magnitude of the force exerted on the object."
The rate of change of momentum of an object is directly proportional to the resultant force applied.
The rate of change of momentum of an object is inversely proportional to the resultant force applied.
Change in momentum of an object is inversely proportional to the resultant force applied.
Change in momentum of an object is directly proportional to the resultant force applied.
- 1 Newton
- 10 Newton
- cannot be determined
- 9.8 N
A force acting on a body produces a constant acceleration. The equation written is as follows:
F=Km×(V−U)t
F- Force; K-constant;
m- mass; V- final velocity
U- initial velocity; t- time taken
a- acceleration; P- momentum
The equation can also be written as
F = m*p/t
F = m*p
F = m*a
F = 2 m*a
A force acting on a body of produces an acceleration of . An other force acting on the another body of mass produces an acceleration of . Find the ratio of .
A car of mass 500 kg is accelerating at 2 ms−2. What is the net force acting on the car?
- 500 N
- 250 N
- 1000 N
- 1500 N
- displacement
- acceleration
- force
- momentum
- 15
- 30
- 60
- 10
Two objects moving along the same straight line are leaving point A with an accelerations and , and velocities and respectively at time . The distance moved by the objects with respect to point A when one object overtakes the other is
- 0.5 m/s2
- 0.05 m/s2
- −0.5 m/s2
- −0.05 m/s2
What is the magnitude of force needed to produce an acceleration of 4 ms−2 in a ball of 6 kg?
20 N
26 N
30 N
24 N
- 120 N
- 240 N
- 480 N
- 720 N
- F=mg
- F=mg
- F=ma
- F=ma
A car of mass 500 kg is accelerating at 2 ms−2. What is the net force acting on the car?
- 500 N
- 250 N
- 1000 N
- 1500 N
- 90 kg
- 10 kg
- 50 kg
- 40 kg
- 4000 N
- 3000 N
- 4500 N
- 3500 N
- mass of the body
- size of the body
- shape of the body
- none of these
- 1000 N
- 2000 N
- 4000 N
- 10000 N
____ is the force when acting on the body of mass _____ produces an acceleration of .
- 30
- 10
- 15
- 60
- 18^i+6^j
- 18^i+12^j
- 12^i+6^j
- None of these
Calculate the force required to accelerate a car from rest to a velocity of 30 ms−1 in 10 seconds. The mass of the car is 1500 kg.
4000 N
3500 N
3000 N
4500 N
- 20 kg
- 15 kg
- 5 kg
- 10 kg
While an athlete is running at a constant acceleration of 4.5 m s−2, he exerts a force of 300 N. What is the mass of the athlete?
64 kg
69.6 kg
65 kg
66.67 kg
- 4000 N
- 3000 N
- 4500 N
- 3500 N