A force of 10 Newton acts on a body of mass 2kg for 3seconds initially at rest calculate velocity acquired by the body and change in momentum of the body

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A force 2^i+^j+^k newtons acts on a body which is initially at rest. lf the velocity of the body at the end of 20 seconds is 4^i+2^j+2^k ms−1, the mass of the body

The correct option is D 10 kgConsidering that at the end of 20 sec, velocity is given by 4^i+2^j+2^k. therefore acceleration is given by, a=v/t.a=4^i+2^j+2^k20Now using m=F/a and F=2^i+^j+^kHence , m = 10 kg

A force $2^i +^j +^k$ newtons acts on a body which is initially at rest. lf the velocity of the body at the end of 20 seconds is $4^i + 2^j + 2^k {m s}^{- 1}$ , the mass of the body

The correct option is D 10 kg
Considering that at the end of 20 sec, velocity is given by $4^i + 2^j + 2^k$ . therefore acceleration is given by, $a = v / t$ .
$a = \frac{4^i + 2^j + 2^k}{20}$
Now using $m = F / a$ and $F = 2^i +^j +^k$
Hence , m $=$ 10 kg