Inverting the Terms of an Inequation

Q.

Find the range of values of x which satisfy $\frac{-1}{3}\le \frac{x}{2}-\frac{4}{3}<\frac{1}{6}$, where x ϵ real number.

1. $2\le x<3$
2. $2\le x\le 3$
3. $3\le x<2$
4. $2<x<3$

Q. Solve: $2\frac{2}{3}+3\frac{1}{2}.$

Q. Solve: $\frac{3}{5}+\frac{2}{7}$

Q.

x > 5 is also same as $\frac{1}{x}<\frac{1}{5}$

1. True

2. False

Q.

Solve : $\frac{5x}{8}>\frac{15}{8}$

1. $x<3$

2. $x>4$

3. $x<4$

4. $x>3$

Q.

$\text{Solve for x:}$

$\frac{x}{3}+\frac{7}{2}=\frac{3}{2}$

1. 5

2. -5

3. -6

4. 6

Q.

Which of the following about x > y is true ?

1. We can change the inequality sign by taking reciprocal of the terms

2. We cannot take reciprocals of the terms

3. Any change in the terms will not make changes to the inequality

4. x > y is invalid

Q.

The inequality $x\le y$ is same as ___ .(Consider x and y are positive integers.)

1. $x\ge y$

2. $\frac{1}{x}\ge \frac{1}{y}$

3. $\frac{1}{x}\ge \frac{y}{1}$

4. $\frac{1}{x}\le \frac{1}{y}$

Q.

Given that x > y; then $\frac{1}{x}<\frac{1}{y}$

1. True

2. False

Q.

$\text{Solve for x:}$

$\frac{x}{3}+\frac{7}{2}=\frac{3}{2}$

1. -6

2. -5

3. 6

4. 5

Q.

$\text{Solve for x:}$

$\frac{x}{3}+\frac{7}{2}=\frac{3}{2}$

1. 5

2. -5

3. 6

4. -6

Q.

Find the range of values of x which satisfy $\frac{-1}{3}\le \frac{x}{2}-\frac{4}{3}<\frac{1}{6}$, where x ϵ real number.

1. $3\le x<2$
2. $2\le x\le 3$
3. $2\le x<3$
4. $2<x<3$