Solve for x-x-3 - 7-2 - 3-2

Given, x/3 + 7/2 = nbsp;3/2 Transposing nbsp; 7/2 to RHS, we get ⇒ x/3= 3/2 7/2 nbsp; ⇒ x/3= 4/2 nbsp; ⇒ x/3= 2 nbsp; Multiplying both s ...

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Byju's Answer

Standard VII

Mathematics

Inverting the Terms of an Inequation

Solve for x:x...

Question

$Solve for x:$

$\frac{x}{3} + \frac{7}{2} = \frac{3}{2}$

-6

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-5

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Solution

The correct option is A
-6

$Given, \frac{x}{3} + \frac{7}{2} = \frac{3}{2}$

$Transposing \frac{7}{2} to RHS, we get$

$\Rightarrow$ $\frac{x}{3} = \frac{3}{2} - \frac{7}{2}$

$\Rightarrow$ $\frac{x}{3} = - \frac{4}{2}$

$\Rightarrow$ $\frac{x}{3} = - 2$

Multiplying both sides by 3, we get

$x = - 6$

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Similar questions

$Solve for x:$

$\frac{x}{3} + \frac{7}{2} = \frac{3}{2}$

Q. Using appropriates, find:

\frac{2}{3} \times \frac{- 5}{7} + \frac{7}{3} + \frac{2}{3} \times \frac{- 2}{7}

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Question 6

Q. Simplify :

\frac{3^{5} 2^{2} 7^{3}}{7^{2} 3^{3} 2^{4}}

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Solve for x: x3+72=32

The correct option is A -6 Given, x3+72=32 Transposing 72 to RHS, we get ⇒ x3=32−72 ⇒ x3=−42 ⇒ x3=−2 Multiplying both sides by 3, we get x=−6

$Solve for x:$

$\frac{x}{3} + \frac{7}{2} = \frac{3}{2}$