Diborane
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reacts with to form an adduct. The shapes of cation and anion in the adduct are respectively:
Square planar, trigonal bipyramidal
Square planar, octahedral
T-shaped, octahedral
Square pyramidal, octahedral
2) How will you carry out the following conversion?
- 3B2H6⋅2NH3
- (BN)2
- B3N3H6
- (BN)4
- H2, H3BO3
- HCl, KBO3
- H2O, KBO3
- H2O, KBO2
- It has only two bridging hydrogens
- When methylated, the product formed is Me4B2H2
- The bridging hydrogen atoms are in a plane perpendicular to the other ones
- All the B-H bonds are of equal lengths
- Hybridisation of Boron changes
- Metal M can be Li or Na
- Geometry around boron is tetrahedral in both reactant and product
- Boron hydrides are used as reducing agent
Which one of the following statements is not true regarding diborane?
It has two bridging hydrogenes and four perpendicular to the rest
When methylated, the product is Me4B2H2
The bridging hydrogenes are in a plane perpendicular to the rest.
All the B-H bond distances are equal.
- an oxidising product B2O3
- a adduct 2BH3.CO
- an oxidising product 2BH3.CO
- an oxidising product BH3
- 12 electrons are involved in bonding
- It has four (2 centre-2 electron) bonds
- It has two (three centre-two electron) bonds
- X does not react with ammonia
- four 2C−2e bonds and two 3C−2e bonds
- two 2C−2e bonds and four 3C−2e bonds
- two 2C−2e bonds and two 3C−2e bonds
- four 2C−2e bonds and four 3C−2e bonds
- Small amines like NH3, CH3NH2 give unsymmetrical cleavage of diborane
- Large amines such as (CH3)3N and pyriding gives symmetrical cleavage of diborane
- Small as well as large amines both gives symmetrical cleavage of diborane
- (A) and (B) both
Diborane
is electron deficient
burns spontaneously in air
has 3c-2e bonds
all of the above
- Si−M, SiO2−X, Na2SiO3−Y, SiCl4−Z
- Al−M, Al(OH)3−X, NaAlO2−Y, AlCl3−Z
- Mg−M, Mg(OH)3−X, NaMgO3−Y, MgCl2−Z
- Ca−M, Ca(OH)2−X, Na2CO3−Y, NaHCO3−Z
- BH3 and B2H6
- NaBH4 and C6H6
- B2H6 and B3N3H6
- B4C3 and C6H6
LiH+B2H6Ether−−−→A. A is as follows
LiBH
LiBH2
LiBH4
None of these
B2H6.2NH3Δ−−−→200∘CA+H2. A is as follows
B3N3H6
B2N2H6
B4N4H6
None of these
1. Colourless gas
2. Coloured gas
3. Toxic gas
4. Non-toxic gas
- 1, 2
- 1, 3
- 1, 2, 3
- 2, 4
- Diborane
- LiBH4
- LiAlH4
- NaBH3CN
- Toluene
- Benzene
- Aniline
- Phenol
- 4
- 6
- 8
- 2
In which of the following, a salt of type KMO2 (M = Al or B) is obtained?
- H2, H3BO3
- HCl, KBO3
- H2O, KBO3
- H2O, KBO2
- B2H6+NH3(excess)low temperature−−−−−−−−−→
- B2H6+NH3(excess)high temperature−−−−−−−−−−−−−−−−−−→Higher temperature (>200oC)
- B2H6+NH3high temperature(200oC)−−−−−−−−−−−−−−−→ratio 2NH3:1B2H6
- None of these
- 12 electrons are involved in bonding
- It has four (2 centre-2 electron) bonds
- It has two (three centre-two electron) bonds
- X does not react with ammonia
An alkene ‘A’ contains three C – C, eight C – H σ bonds and one C – C π bond. ‘A’ on ozonolysis gives two moles of an aldehyde of molar mass 44 u. Write IUPAC name of ‘A’.