Elevation in Boiling Point
Trending Questions
(JEE Main - 2017)
- 0.325
- 0.486
- 0.162
- 0.675
0.1 M NaCl and 0.1 M CH3COOH are kept in separate containers. If their osmotic pressures Are P1 and P2 respectively then the correct statement is:
- P1> P2
P1= P2
P1< P2
P1= P2 = 0 atm
The rise in the boiling point of a solution containing 1.8 gram of glucose in 100g of a solvent in 0.10C. The molal elevation constant of the liquid is
0.01 K/m
0.1 k/m
1 K/m
10 K/m
Which one of the following aqueous solutions will exhibit highest boiling point?
0.015 M urea
0.01 M KNO3
0.01 M Na2SO4
0.015 M glucose
Which one of the following would produce maximum elevation in boiling point?
0.1 M glucose
0.2 M glucose
0.1 M barium chloride
0.1 M magnesium sulphate
If 0.15g of a solute dissolved in 15g of solvent is boiled at a temperature higher by 0.2160C than that of the pure solvent, then the molecular weight of the
substance is (molal elevation constant for the solvent is 2.16):
1.01
10
10.1
100
A 0.2 molal aqueous solution of a weak acid (HX) is 20% ionised. The freezing point of this solution is (Given for water)
- 0.31° C
- 0.45°C
- 0.53°C
- 0.90°C
Which of the following statements is correct for the boiling point of solvent containing a dissolved solid substance
- Boiling point of the liquid is depressed
- Boiling point of the liquid is elevated
- There is no effect on the boiling point
- The change depends upon the polarity of liquid
The boiling point of benzene is 353.23 K. When 1.80 g of a non-volatile solute was dissolved in 90 g benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute. (Kb for benzene is 2.53Kkgmol−1)
58.0gmol−1
68.0gmol−1
78.0gmol−1
48.0gmol−1
The boiling point of a solution of 0.105 gm of a substance in 15.84 gram of ether was found to be 100°C higher than that of pure ether. What is the molecular weight of the substance [Molecular elevation constant of ether per 100 g = 21.6]
144.50
143.18
140.28
146.66
18g of glucose (C6H12O6) is dissolved in 1 kg of water in a saucepan. At what temperature will the water boil (at 1 atm)? Kb for water is 0.52Kkgmol−1.
373.202K
365.202K
370.202K
473.202K
Normal boiling point of water is 373 K (at 760mm). Vapour pressure of water at 298 K is 23 mm. If the enthalpy of evaporation is 40.656 kJ/mole, the boiling point of water at 23 mm pressure will be
250 K
294 K
51.6 K
12.5 K
- −0.481 ∘C
- −0.360 ∘C
- −0.260 ∘C
- −0.150 ∘C
- 0.32
- 0.64g
- 0.96g
- 0.16g
A 0.001 molal solution of in water had a freezing point depression of 0.0054°C. If Kf for water is 1.80, the correct formulation for the above molecule is
0.1 M NaCl and 0.1 M CH3COOH are kept in separate containers. If their osmotic pressures Are P1 and P2 respectively then the correct statement is:
- P1> P2
P1= P2
P1< P2
P1= P2 = 0 atm
Given :
Boiling point of pure solvent is 127∘C
Molecular mass of the solvent is 20 g mol−1
- 2.4 K kg mol−1
- 0.5 K kg mol−1
- 1.6 K kg mol−1
- 3.2 K kg mol−1