Equation of Tangent in Point Form
Trending Questions
Q. The line 4x + 4y – 11 = 0 intersects the circle x2+y2−6x−4y+4=0 at A and B. The point of intersection of the tangents at A, B is
- (–1, – 2)
- (1, 2)
- (–1, 2)
- (1, –2)
Q.
The radius of the circle passing through the point , two of whose diameters are and is
Q.
___
If the point of contact of the circle x2+y2−30x+6y+109=0 with the tangent 11x - 2y - 46 = 0 is (a, b), find a + b
Q. If the line x + y = 5 is a tangent to the circle x2+y2−2x−4y+3=0, then the coordinates of the point of contact are .
- (2, 3)
- (-2, -3)
- (-2, 3)
- (2, -3)
Q. If a tangent to the circle x2+y2=1 intersects the coordinate axes at distinct points P and Q, then the locus of the mid-point of PQ is:
- x2+y2−2xy=0
- x2+y2−2x2y2=0
- x2+y2−4x2y2=0
- x2+y2−16x2y2=0
Q. The equation of the tangent drawn to the circle x2+y2=4 at the point whose polar coordinates are given by (2, π3) is
- x+√3 y=2
- √3 x+y=2
- x+√3 y=4
- √3 x+y=4
Q. A chord of the circle x2+y2−4x−6y=0 passing through the origin subtends an angle tan−1(74) at the point where the circle meets positive y-axis. Equation of the chord is
- 2x + 3y = 0
- x + 2y = 0
- x – 2y = 0
- 2x – 3y = 0
Q. The equation of the tangents to the circle x2+y2=a2, which makes a triangle of area a2 sq. units with coordinate axes, is/are
- x+y=a√2
- x−y=a√2
- 2x+3y=2a√3
- 2x−3y=2a√3
Q. Two tangents are drawn on the circle x2+y2−6x−2y−15=0 at point B(3, 6) and D(0, −3) which meets at point C. If A be the center of circle, then area of quadrilateral ABCD is
Q. The point of contact of the tangent to the circle x2+y2=5 at the point (1, -2) which touches the circle x2+y2−8x+6y+20=0, is
- (2, -1)
- (3, -1)
- (4, -1)
- (5, -1)
Q.
If the point of contact of the circle x2+y2−30x+6y+109=0 with the tangent 11x - 2y - 46 = 0 is (a, b), find a + b
Q. The circle C1:x2+y2=8 cuts orthogonally the circle C2 whose centre lies on the line x−y−4=0 then, the circle C2 passes through a fixed point, which lies on
- x−2y=0
- x+y=0
- x−2y=0
- x+2y=0
Q. Consider the relation 4l2−5m2+6l+1=0, where l, m∈R. If the line lx+my+1=0 touches a fixed circle, then the centre of that circle is:
- (0, 5)
- (3, 0)
- (2, 1)
- (3, −3)
Q. From the point (1, −2, 3), lines are drawn to meet the sphere x2+y2+z2=4 and they are divided internally in the ratio 2:3. The locus of the point of division is
- 5x2+5y2+5z2−6x+12y+2z=0
- 5x2+5y2+5z2−2xy−3yz−zx−6x+12y+5z=0
- 5(x2+y2+z2)=22
- None of these