Monosaccharide Anomers
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Q. Assertion :The two cyclic hemiacetal forms of glucose, α− form and β− form are called anomers. Reason: Anomers differ only in the configuration of the hydroxyl group at C−1.
- Both Assertion and Reason are correct and Reason is the correct explanation for Assertion
- Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion
- Assertion is correct but Reason is incorrect
- Both Assertion and Reason are incorrect
Q. Consider the following statements: D-glucose, D-galactose and D-fructose are all
1.Isomers
2.Epimers
3.Aldohexoses
4.Monosaccharides
Which of the above statements are correct?
1.Isomers
2.Epimers
3.Aldohexoses
4.Monosaccharides
Which of the above statements are correct?
- 1 and 4
- 1, 2 and 3
- 2 and 4
- 1, 2 and 4
Q.
α - D - glucose and β - D - glucose differ from each other due to the difference in one of the carbons with respect to its ________.
- Number of OH groups
- Conformation
- Size of hemiacetal ring
- Configuration
Q. When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ______ carbon atom, because:
- D, the carbonyl group is drawn to the right
- L, the carbonyl group is drawn to the left
- Acetal, it forms bond to an −OR and an −OR′
- Anomeric, its substituents can assume an β or α position
Q. The two forms of D-glucopyranose obtained from the solution of D-glucose are called:
- enantiomer
- epimer
- anomer
- isomer
Q. Pyranose ring structure of glucose is due to hemiacetal formation between:
- C1and C5
- C2and C4
- C1and C4
- C1and C3
Q. Two forms of D-glucopyranose, are called_________.
- enantiomers
- diastereomers
- anomers
- epimers
Q. The molecular formula for glucose is C6H12O6. What would be the formula for a polymer made by linking ten glucose molecules together by dehydration reactions?
- C20H120O60
- C60H100O50
- C60H102O51
- C60H111O51
Q. Identify the correct set of stereochemical relationships amongst the following monosaccharides −I−IV.
- I and II are anomers; III and IV are epimers.
- I and II are epimers; II and IV are anomers
- I and III are epimers; III and IV are anomers
- I and III are anomers; I and II are epimers
Q. Methyl α-D-glucoside is actually a:
- hemi-acetal
- carboxylic acid
- acetal
- amine
Q. The correct statements about anomers are:
- Anomer have different stereochemistry at the anomeric carbon atom
- α−D−Glucopyranose and β−D−Glucopyranose are anomers
- α−D−Glucopyranose and β−D−Glucopyranose are diastereomer
- When pure α−D−Glucopyranose is dissolved in water its optical rotation slowly changes
Q. The term anomers of glucose refers to:
- isomers of glucose that differ in configurations at carbons one and four (C-1 and C-4)
- a mixture of (D)-glucose and (L)-glucose
- enantiomers of glucose
- isomers of glucose that differ in configuration at carbon one (C-1)
Q. The specific rotation of two glucose anomers are α=+110∘ and β=+19∘ and for the constant equilibrium mixture is +52.7∘. Calculate the percent composition of the anomers in the equilibrium mixture.
Q. The two form of D-glucopyranose obtained from the solution of D-glucose are called
- Isomer
- Anomer
- Epimer
- Enantiomer
Q. The term anomers of glucose refers to:
- isomers of glucose that differs in configuration at carbons one and four (C-1 and C-4)
- a mixture of (D-) glucose arid (L-) glucose
- enantiomers of glucose
- isomers of glucose that differ in configuration at carbon one (C-1)
Q. Three cyclic structures of monosaccharides are given below. Which of these are anomers?
- II and III
- I and II
- I and III
- III is anomer of I and II
Q. The two forms of D-glucopyranose obtained from D-glucose are known as:
- epimers
- enantiomers
- geometrical isomers
- anomers
Q. Write a reaction which shows that all the atoms in glucose are linked in a straight chain.
Q. α-D-glucose and β-D-glucose are examples of:
- enantiomers
- tautomers
- anomers
- epimers