CFSE in Octahedral and Tetrahedral Complexes
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Which of these statements about [Co(CN)6]3− is true?
[Co(CN)6]3− has four unpaired electrons and will be in a low-spin configuration.
[Co(CN)6]3− has four unpaired electrons and will be in a high-spin configuration.
[Co(CN)6]3− has no unpaired electrons and will be in a high-spin configuration.
[Co(CN)6]3− has no unpaired electrons and will be in a low-spin configuration.
Why is square planar?
For a high spin metal ion in the octahedral and tetrahedral fields, the values of the crystal field stabilisation energies are
(Δ0= crystal feild splitting energy in an octahedral feild, P= Electron pairing energy)
- −125Δ0+P
- −125Δ0+3P
- −25Δ0+2P
- −25Δ0+P
Consider that a metal ion forms a complex with aqua ligands, and the spin only magnetic moment of the complex is . The geometry and the crystal field stabilization energy of the complex is:
Tetrahedral and
Tetrahedral and
Octahedral and
Octahedral and
The species that has a spin only magnetic moment of is
The colour of the coordination compounds depends on the crystal field splitting. What will be the correct order of absorption of wavelength of light in the visible region, for the complexes, [Co(NH3)6]3+, [Co(CN)6]3−, [Co(H2O)6]3+
[Co(NH3)6]3+, [Co(CN)6]3−, [Co(H2O)6]3+
(a) [Co(CN)6]3−>[Co(NH3)6]3+>[Co(H2O)6]3+
(b) [Co(NH3)6]3+>[Co(H2O)6]3+>[Co(NH3)6]3+
(c) [Co(H2O)6]3+>[Co(NH3)6]3+>[Co(CN)6]3−
(d) [Co(CN)6]3−>[Co(NH3)6]3+>[Co(H2O)6]3+
- Δt ≈ 49Δo
- Δo≈ 49Δt
- Δt ≈ 12Δo
- Δo ≈ 2Δt
Which of the following complex is/are low spin complex(es)?
[Co(NH3)6]3+
- [CoF6]3−
[Fe(H2O)6]2+
- [Fe(CN)6]4−
What is crystal field splitting energy? How does the magnitude of Δ0 decide the actual configuration of d-orbitals in a coordination entity?
(Note: py = pyridine
Given: Atomic numbers of Fe, Co, Ni and Cu are 26, 27, 28 and 29, respectively)
- [FeCl4]− and [Fe(CO)4]2−
- [Co(CO)4]− and [CoCl4]2−
- [Ni(CO)4]− and [Ni(CN)4]2−
- [Cu(py)4]+ and [Cu(CN)4]3−
[Co(NH3)6]3+
[CoCl(NH3)5]2+
[Co(CN)6]3–
[Co(NH3)5(H2O)]3+
The spin-only magnetic moment value of the
complex that absorbs light with shortest wavelength
is
Among the following pairs of complexes, in which case is the Δ0 value is higher for the first one?
[Co(NH3)6]3+ and [Co(CN)6]3−
[Co(H2O6]2+ and [Co(H2O)6]3+
[Co(H2O6]3+>[Rh(H2O)6]3+
[Rh(H2O)6]3+ and [Co(H2O6]3+
Why are low spin tetrahedral complexes not formed?
- (π 2py) < (σ 2pz) > (π∗2px)≈ (π∗2py)
- (π 2py) > (σ 2pz) > (π∗2px)≈ (π∗2py)
- (π 2py) < (σ 2pz) > (π∗2px)≈ (π∗2py)
- (π2py)< (σ 2pz)<(π∗2px)≈ (π∗2py)
NO−3, H2O2, BF3, PCl3, XeF4, SF4, XeO3, PH+4, SO3, [Al(OH)4]−
The CFSE for octahedral [CoCl6]4− is 18000 cm−1. The CFSE for tetrahedral [CoCl4]2− will be
List-IList-II(Compound)(Shape)(A)BrF5(I)bent(B)[CrF6]3−(II)square pyramidal(C)O3(III)trigonal bipyramidal(D)PCl5(IV)octahedral
Choose the correct answer from the options given below :
- (A)-(I), (B)-(II), (C)-(III), (D)-(IV)
- (A)-(III), (B)-(IV), (C)-(II), (D)-(I)
- (A)-(II), (B)-(IV), (C)-(I), (D)-(III)
- (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
Jahn-Teller effect is not observed in high spin complexes of
d8
d4
d7
d9
- Square planar, tetrahedral and octahedral
- Octahedral, square planar and octahedral
- Octahedral, tetrahedral and square planar
- Tetrahedral, square planar and octahedral
How many nodal surface can orbital can have?
ScTiVCrMnFeCoNiCuZn
Answer the following:
(i) Write the element which is not regarded as a transition element. Give reason.
(ii) Which element has the highest m.p.?
(iii) Write the element which can show an oxidation state of +1.
(iv) Which element is a strong oxidizing agent in +3 oxidation state and why?
(i) Transition metals show variable oxidation states.
(ii) Zn, Cd and Hg are soft metals.
(iii) Eo value for the Mn3+/Mn2+ couple is highly positive (+ 1.57 V) as compared to Cr3+/Cr2+.
(b) Write one similarity and one difference between the chemistry of lanthanoid and actinoid elements.
(l) Both the complexes can be high spin.
(ll) Ni(ll) complex can very rarely be of low spin.
(lll) With strong field ligands, Mn(ll) complexes can be low spin.
(lV) Aqueous solution of Mn(ll) ions is yellow in color.
The correct statements are:
- (l), (ll) and (lll) only
- (l), (lll) and (lV) only
- (l) and (ll) only
- (ll), (lll) and (lV) only
(i) The chemistry of actinoids is more complicated as compared to lanthanoids.
(ii) Transition metals form complex compounds.
(b) Complete the following equation :
2MnO−4+6H++5SO2−3→
- Δt=49Δ∘
- Δt=12Δ∘
- Δ∘=−2Δt
- Δ∘=−49Δt
- [Co(CN)6]3−>[Co(NH3)6]3+>[Co(H2O)6]3+
- [Co(NH3)6]3+>[Co(H2O)6]3+>[Co(CN)6]3−
- [Co(H2O)6]3+>[Co(NH3)6]3+>[Co(CN)6]3−
- [Co(NH3)6]3+>[Co(CN)6]3−>[Co(H2O)6]3+