Comparison of Lanthanides and Actinides
Trending Questions
Q.
Write some similarities and differences between Lanthanide and Actinide.
Q. Which of the following is not a transition element?
- Cu
- Ac
- Zn
- Pd
Q. LiCl is more covalent than KCl. Why ?
Q.
Compare the chemistry of actinoids with that of the lanthanoids with special reference to
Electronic configuration
Atomic and ionic sizes
Oxidation state
Q. (i) With reference to structural variability and chemical reactivity, write the differences between lanthanoids and actinoids.
(ii) Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state.
(iii) Complete the following equation :
MnO−4+8H++5e−→
(iv) Out of Mn3+ and Cr3+, which is more paramagnetic and why ?
(Atomic nos. : Mn = 25, Cr = 24)
(ii) Name a member of the lanthanoid series which is well known to exhibit +4 oxidation state.
(iii) Complete the following equation :
MnO−4+8H++5e−→
(iv) Out of Mn3+ and Cr3+, which is more paramagnetic and why ?
(Atomic nos. : Mn = 25, Cr = 24)
Q.
Name two other elements belonging to the same family as Carbon.
Q. Statement 1: Lanthanides have much less tendency to form complexes than actinides.
Statement 2: Compared to actinides, the lanthanides have relatively larger size of atoms and less nuclear charge.
Statement 2: Compared to actinides, the lanthanides have relatively larger size of atoms and less nuclear charge.
- Statement 1 is True, statement 2 is True, statement 2 is a correct explanation of statement 1
- Statement 1 is True, statement 2 is True, statement 2 is not a correct explanation of statement 1
- Statement 1 is true, Statement 2 is False
- Statement 1 is False, Statement 2 is True
Q.
Is plutonium man-made?
Q. Give one point of dissimilarity between lanthanides and actinides.
Q. Compare the chemistry of actinoids with that of the lanthanoids with special reference to: (i) electronic configuration (ii) atomic and ionic sizes and (iii) oxidation state (iv) chemical reactivity.
Q. Differentiate Lanthanides and Actinides.
Q. General electronic configuration of actionoids is (n−2)f1−14(n−1)d0−2ns2. Which of the following actinoids have one electron in 6d orbital?
- U (Atomic no. 92)
- Np (Atomic no. 93)
- Pu (Atomic no. 94)
- Am (Atomic no. 95)
Q. Electronic configuration of chlorine is :
- 1s22s22p63s13p6
- 1s22s22p53s23p6
- 1s22s22p64s24p5
- 1s22s22p63s23p5
Q. Element 'A' has electronic configuration 2, 7, 'B' has configuration 2, 8, 6, 'C' has configuration 2, 8, 8 while 'D' has 2, 8, 7. Which element will show similar chemical properties?
- A and C
- A and D
- B and D
- B and C
Q. How many electrons are present in M-shell of an element with atomic number 20?
- 8
- 18
- 2
- 6
Q. Can hexadentate Ligand act as a pentadentate or tetradentate?
Q. Actinides exhibit a larger number of oxidation state than that of corresponding lanthanides. The reason behind this aspect is :
- lesser energy difference between 5f and 6d-orbitals than between 4f and 5d-orbitals
- larger atomic size of actinides than the lanthanides
- more energy difference between 5f and 6d orbitals than between 4f and 5d-orbitals
- greater reactive nature of the actinides than the lanthanides
Q.
The actinoids exhibit more number of oxidation states in general than lanthanoids because:
- the 5f orbitals are more buried than the 4f orbitals
- the 5f orbitals extend further from the nucleus than the 4f orbitals
- the actinoids are more reactive than the lanthanoids
- there is a similarity between 4f and 5f orbitals in their angular part of the wave function
Q. The electronic configuration of valence shell of Cu is:
- 3d104s2
- 3d94s2
- 3d104s1
- 3d104s0
Q. The point of dissimilarity between lanthanides and actinides is:
- three outermost shells are partially filled
- they show oxidation of +3 ( common)
- they are called inner transition elements
- they are radioactive in nature
Q. The electronic configuration of an element with atomic number 29 is :
- 1s2, 2s2, 2p6, 3s2, 3p6, 3d9, 4s2
- 1s2, 2s2, 2p6, 3s2, 3p6, 3d10, 4s1
- 1s2, 2s2, 2p6, 3s2, 3p6, 3d8, 4s2, 4p1
- 1s2, 2s2, 2p6, 3s2, 3p6, 3d7, 4s2, 4p2
Q. (i) Write down any three difference between Lanthanoid and Actinoid ?
(ii) The melting and boiling points of Zy. Cd and Hg are low. Why ?
(iii) Draw the structure of manganate ion.
(ii) The melting and boiling points of Zy. Cd and Hg are low. Why ?
(iii) Draw the structure of manganate ion.
Q. Identify the incorrect statement among the following -
- La and Lu have partially filled d-orbitals and no other partially filled orbitals
- d-block elements shows irregular and erratic chemical properties among themselves
- The chemistry of various lanthanoids is very similar
- 4f and 5f-orbitals are equality shielded
Q. Which of the following cannot form oxo ion?
- CeO+2
- PuO+2
- NpO+2
- UO2+2
Q. Donor atom in sulphate ligand, sulphate ligand?
Q. why chelate ligand more stable than monodentate ligand
Q. The number of oxidation states is exhibited by the actinoids more than by the lanthanide. The main reason for this is:
- more energy difference between 5f and 6d orbitals than that between 4f and 5d orbitals.
- the lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals.
- the greater metallic character of the lanthanoids than that of the corresponding actinoids.
- more active nature of the actinoids.
Q. Which electronic configuration is most stable?
- 3d04s1
- 3d24s0
- 3d54s1
- 3d14s2
Q. The main reason for larger number of oxidation states exhibited by the actinoids than the corresponding lanthanoids, is:
- the lesser energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
- more energy difference between 5f and 6d orbitals than between 4f and 5d orbitals
- greater reactive nature of the actinoids than the lanthanoids
- larger atomic size of actinoids than the lanthanoids
Q. (a) How would you account for the following:
(i) The chemistry of actinoids is more complicated as compared to lanthanoids
(ii) Transition metals form complex compounds
(b) Complete the following equation:
2MnO4−+6H++SO32−⟶
(i) The chemistry of actinoids is more complicated as compared to lanthanoids
(ii) Transition metals form complex compounds
(b) Complete the following equation:
2MnO4−+6H++SO32−⟶