Dalton's Law of Partial Pressures
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- The initial mixture taken should be an equimolar mixture of A and B
- The first vapours formed will have more moles of A as compared to moles of B
- PA=1000 mm of Hg
- The vapour pressure above the condenstate will be 920 mm of Hg at same temparature
What is the difference between vapor pressure and partial pressure?
Equal masses of methane and oxygen are mixed in an empty container at 25 degrees centigrade. The fraction of the total pressure exerted by Oxygen is:
Options1)1/3
2)1/2
3)2/3
4)1/3*273/298
Answer is option1
- O2 and CO2
- N2 and O2
- Cl2 and O2
- NH3 and HCl
At 300K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is (-)
[Given: \ln1.35=0.3 and R=8.3JK−1mol−1]
temperature at which the flask will burst is _____∘C. [Nearest integer]
(Given: R=8.3 J K–1 mol–1, Atomic masses of C and H are 12u and 1u, respectively.) (Assume that
propane behaves as an ideal gas.)
the vapour pressure of two liquids A and B in their pure states are in ratio 1:2. A binary solution of A and B has A and B in mole proportion 1:2. The mole fraction of A in vapour phase of the solution will be ??
is the answer 0.33 or 0.2( because as the molefraction of A in vapour phase is used should we not use daltons law of partial pressure??)
A gaseous mixture of an equal mass of and is stored over water. if the total pressure is then the partial pressure of dry gas is ?(aqueous tension )
- PO2=19.75 bar, PNe=5.25 bar
- PO2=12.75 bar, PNe=12.25 bar
- PNe=19.75 bar, PO2=5.25 bar
- PNe=12.75 bar, PO2=12.25 bar
The pressure of a 1:4 mixture of dihydrogen and dioxygen enclosed in a vessel is one atmosphere. What would be the partial pressure of dioxygen?
(a) 0.8×105 atm (b) 0.008 Nm−2 (c) 8×104 Nm−2 (d) 0.25 atm
A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.
Two solids dissociated as follows
The total pressure when both the solids dissociate simultaneously is:
- p(O2)=0.785 p(N2)
- p(O2)=8.75 p(N2)
- p(O2)=11.4 p(N2)
- p(O2)=0.875 p(N2)
- 15.45
- 14.45
- 17.45
- 16.45
A and B are ideal gases. The molecular weights of A and B are in the ratio of 1 : 4 . The pressure of a gas mixture containing equal weights of A and B is P atm. What is the partial pressure (in atm) of B in the mixture?
P/5
P/2
P/2.5
3P/4
- Raoult's law is obeyed for entire concentration range and temperatures
- ΔHmix=0
- ΔVmix=0
- ΔSmix=0
- 0.0375 M
- 0.028 M
- 0.0562 M
- 0.0187 M
- Both assertion and reason are true and reason is the correct explanation of assertion
- Both assertion and reason are true but reason is not the correct explanation of assertion
- Assertion is true but reason is false
- Both assertion and reason are false
- 0.487
- 0.352
- 0.892
- 0.665
The gas having the highest partial pressure in the atmosphere is –
PCl5(g)⇌PCl3(g)+Cl2(g)
PCl5 gas at a certain pressure is introduced in the container at 27 oC. However, the total pressure at equilibrium at 207 oC was found to be double the initial value. The % dissociation of PCl5 at 207 oC is:
A gaseous mixture of three gases A, B and C has a pressure of 10atm. The total number of moles of all gases is 10. The partial pressure of A and B are 3 and 1 atm respectively. If C has a molecular weight of 2, then find the weight of C in grams present in the mixture.
6
3
12
8
Dalton’s law of partial pressure is not applicable to a mixture of