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Question

A mixture of dihydrogen and dioxygen at one bar pressure contains 20% by weight of dihydrogen. Calculate the partial pressure of dihydrogen.


Solution

Let the weight of dihydrogen be 20 g and the weight of dioxygen be 80 g.
Then, the number of moles of dihydrogen, nH2=202=10 moles and the number of moles
of dioxygen, nO2=8032=2.5 moles
Given,
Total pressure of the mixture, ptotal=1 bar
Then, partial pressure of dihydrogen,
pH2=nH2nH2+nO2×Ptotal=1010+2.5×1=0.8 bar
Hence, the partial pressure of dihydrogen is 0.8 bar


Chemistry
NCERT Textbook
Standard XI

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