Geometrical Isomerism in Square Planar Geometry
Trending Questions
- Epimers
- Enantiomers
- Mesomers
- Diastereomers
Indicate the complex ion which shows geometrical isomerism.
(a) [Cr(H2O)4Cl2]+
(b) [Pt(NH3)3Cl]
(c) [Co(NH3)6]3+
(d) [Co(CN)5(NC)]3−
The number of possible optical isomers for the complexes hybridized metal atom, respectively, is:
Total number of monodentate ligands attached to the central metal ion through coordinate bonds is called the
Coordination sphere of the metal ion
Coordination number of the metal ion
Oxidation number of the metal ion
Ligands
- 8
- 12
- 10
- 14
- cis
- trans
- fac
- mer
- 2
- 3
- 6
- 5
- cis [Pd(Cl)2(NH3)2]
- trans -[Pt(Cl)2(NH3)2]
- cis - [Pt(Cl)2(NH3)2]
- trans - [Pd(Cl)2(NH3)2]
- True
- False
Write all the geometrical isomers of [Pt(NH3)(Br)(Cl)(py)] and how many of these will exhibit optical isomers?
- 4
- 2
- none
- 3
The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH3)(NH2OH)]⨁ is (py = pyridine) :
2
4
3
6
- CH3CH=NOH
- All of these
- structural isomers
- conformational isomers
- geometrical isomers
- optical isomers
[Co(en)3]Cl3
The number of geometric isomers that can exist for square planar [Pt(Cl)(py)(NH3)(NH2OH)]⨁ is (py = pyridine) :
2
3
4
6
- 2
- 4
- 5
- 3
- None of the above
- [Ni(CO)4] is square planar and [Ni(CN)4]2−, [NiCl4]2− are tetrahedral
- [Ni(CN)4]2− is square planar and [NiCl4]2−, [Ni(CO)4] are tetrahedral
- [NiCl4]2− is square planar and[Ni(CN)4]2−, [Ni(CO)4] are tetrahedral
[CoCl3(NH3)3]
- 16
- 12
- 8
- 24
- 0.064
- 0.045
- 0.015
- 0.032
- Tetrahedral
- Square planar
- Both (a) and (b)
- Cannot be predicted