Limitations of First Law
Trending Questions
Q. The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
- △H=18 kcal mol−1
- △H=22 kcal mol−1
- △H=26 kcal mol−1
- △H=30 kcal mol−1
Q. The difference between heat of reactions at constant pressure and constant volume for the reaction C6H6(l)+152O2(g)→6CO2(g)+3H2O(l) at 25∘C in kJ is
- -7.43
- 3.72
- -3.72
- 7.43
Q. What will be the amount of heat evolved by burning 10L of methane under standard conditions?
(Given heats of formation of CH4, CO2 and H2O are −76.2, −398.8 and −241.6 kJmol−1 respectively)
(Given heats of formation of CH4, CO2 and H2O are −76.2, −398.8 and −241.6 kJmol−1 respectively)
- 805.8 kJ
- 398.8 kJ
- 359.7 kJ
- 640.4 kJ
Q. The standard enthalpies of formation of CO2(g), H2O(l) and glucose(s) at 25oC are –400 kJ/ mol, –300‘kJ/ mol and –1300 kJ/ mol, respectively. The standard enthalpy of combustion per gram of glucose at 25oC is
- +16.11kJ
- –16.11kJ
- +2900kJ
- –2900kJ
Q. Ethyl chloride (C2H5Cl) is prepared by reaction of ethylene with hydrogen chloride:
C2H4(g)+HCl(g)→C2H5Cl(g) ΔH=−72.3 kJ/mol
What is the value of ΔE (in kJ), if 98 g of ethylene and 109.5 g of HCl are allowed to react at 300 K ?
C2H4(g)+HCl(g)→C2H5Cl(g) ΔH=−72.3 kJ/mol
What is the value of ΔE (in kJ), if 98 g of ethylene and 109.5 g of HCl are allowed to react at 300 K ?
- −64.81
- −190.71
- −209.41
- −224.38
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. The heat of combustion of acetylene is 312 kcal. If heat of formation of CO2 and H2O are 94.38 and 68.38 kcal respectively, C≡≡C bond energy is xkcal. Given that heat of atomisation of C and H are 150.0 and 51.5 kcal respectively and C−−H bond energy is 93.64 kcal. Value of x
- 161
- 150
- 170
- None of these
Q. The enthpaly combution at 25 ∘C of H2, cyclohexane (C6H12) and cyclohexene (C6H10) are −241, −3920 and −3800 kJ/mol respectively. The heat of hydrogenation of cyclohexenes:
- −121 kJ mol−1
- +121 kJ mol−1
- −242 kJ mol−1
- +242 kJ mol−1
Q. The heat of combustion of acetylene is 312 kcal. If heat of formation of CO2 and H2O are 94.38 and 68.38 kcal respectively, C≡≡C bond energy is xkcal. Given that heat of atomisation of C and H are 150.0 and 51.5 kcal respectively and C−−H bond energy is 93.64 kcal.
Value of x (nearest integer value) is _______.
Value of x (nearest integer value) is _______.
Q. Given,
NH3(g)+3Cl2(g)→NCl3(g)+3HCl; ΔH1
N2(g)+3H2(g)→2NH3(g); ΔH2
H2(g) + Cl2(g)→ 2HCl(g); ΔH3
The heat of formation of NCl3 in terms of ΔH1, ΔH2 and ΔH3 is:
NH3(g)+3Cl2(g)→NCl3(g)+3HCl; ΔH1
N2(g)+3H2(g)→2NH3(g); ΔH2
H2(g) + Cl2(g)→ 2HCl(g); ΔH3
The heat of formation of NCl3 in terms of ΔH1, ΔH2 and ΔH3 is:
ΔH1+ΔH22+32ΔH3
ΔH1−ΔH22−32ΔH3
ΔH1−ΔH22+32ΔH3
ΔH1+ΔH22−32ΔH3
Q. Given, C2H2(g)→C2H4(g):ΔH∘=−175 kJ mol−1
ΔH∘f(C2H4, g)=50kJ mol−1;ΔH∘f(H2O, l)=−280 kJ mol−1;ΔH∘f(CO2g)=−390 kJ mol−1
If ΔH∘ is enthalpy of combustion (in kJ mole−1 of C2H2(g), then calculate the value of ∣∣∣ΔH∘257∣∣∣
ΔH∘f(C2H4, g)=50kJ mol−1;ΔH∘f(H2O, l)=−280 kJ mol−1;ΔH∘f(CO2g)=−390 kJ mol−1
If ΔH∘ is enthalpy of combustion (in kJ mole−1 of C2H2(g), then calculate the value of ∣∣∣ΔH∘257∣∣∣
Q. The combustion of benzene (l) gives CO2(g) and H2O(l). Given that the heat of combustion of benzene at constant volume is —3263.9 kJ mol−1 at 25∘C. The heat of combustion (in kJ mol−1) of benzene at constant pressure will be:
(R=8.314 JK−1mol−1)
(R=8.314 JK−1mol−1)
- -3267.6
- 4152.6
- -452.46
- 3260
Q. The heats of formaton of CO2(g) and H2O(I) are -394 kJ/mole and -285.8 kJ/mole respectively. Using the data for the following combustion reaction, calculate the heat of formation of C3H8(g).
C3H8(g)+5O2(g)→3CO2(g)+4H2O(l) ; ΔH∘rxn=−2221.6kJ
- +212.2
- −143.3
- +185.4
- −103.6
Q. The heat of reaction for C10H8(s)+12O2(g)→10CO2(g)+4H2O(l) at constant volume is −1228.2 Kcal at 25oC. Calculate the heat of reaction at constant pressure and at 25oC.
(Given : R=2×10−3 Kcal K−1 mol−1)
(Given : R=2×10−3 Kcal K−1 mol−1)
- −1229.4 Kcal
- +1229.4 Kcal
- −1227.0 Kcal
- +1227.0 Kcal
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. Combustion of some amount of ethylene, 6235 kJ heat was evolved. The heat of combustion of 1 mole of ethylene is 1511 kJ, What will be the volume of O2 (at NTP) that entered into the reaction is?
- 277.2 mL
- 277.2 litres
- 6226 litres
- 11.2 litres
Q. The formation of the oxide ion O2− involves first an exothermic step followed by an endothermic step as shown below:
O+e−→O−; ΔH=−142 kJmol−1
O+e−→O−; ΔH=−142 kJmol−1
O−+e−→O2−; ΔH=844 kJmol−1
This is because :
- O− ion has comparatively larger size than oxygen atom
- oxygen has high electron affinity
- O− ion will tend to resist the addition of another electron.
- oxygen is more electronegative
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
- △H=18 kcal mol−1
- △H=22 kcal mol−1
- △H=26 kcal mol−1
- △H=30 kcal mol−1
Q. O(g)+e−→O−(g) ΔH1
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
O−(g)+e−→O−2(g) ΔH2
O2(g)→O+2(g)+e− ΔH3
O(g)→O+(g)+e− ΔH4
H2(g)→H+2(g)+e− ΔH5
H(g)→H+(g)+e− ΔH6
O(g)+2e−→O−2 ΔH7
Which of the following option(s) is/are correct?
- |△H1|>|△H2|
- |△H4|>|△H3|
- |△H5|>|△H6|
- |△H7| is +ve
Q. The formation of the oxide ion O2−(g) requires first an exothermic and then an endothermic step as shown below.
O(g)+e−=O−(g), ΔH0=−142 kJmol−1
O−(g)+e−=O2−(g), ΔH0=+844 kJmol−1
O−(g)+e−=O2−(g), ΔH0=+844 kJmol−1
This is because :
- O− ion will tend to resist the addition of another electron
- oxygen has high electron affinity
- O− ion has comparatively larger size than oxygen atom
- oxygen is more electronegative
Q. The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
- △H=18 kcal mol−1
- △H=22 kcal mol−1
- △H=26 kcal mol−1
- △H=30 kcal mol−1
Q. The heat of formation of C2H5OH(l) is −66 kcal mol−1. The heat of combustion of CH3OCH3 (g) is −348 kcal mol−1. △Hf for H2O and CO2 are −68 kcal mol−1 and −94 kcal mol−1 respectively.
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
Then, the △H for reaction C2H5OH(l)→CH3OCH3(g) is :
- △H=18 kcal mol−1
- △H=22 kcal mol−1
- △H=26 kcal mol−1
- △H=30 kcal mol−1