Ostwald Dilution Law Mathematical Interpretation
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At 25∘C, the dissociation constant of a base BOH is 1.0 × 10−12. The
concentration of Hydroxyl ions in 0.01 M aqueous solution of the base
would be
2.0 x 10-6 mol L-1
1.0 x 10-5 mol L-1
1.0 x 10-6 mol L-1
1.0 x 10-7 mol L-1
What is the conc. of acetic acid that must be added to 0.5M HCOOH solution so that the dissociation of both acids is the same? [An example of Isohydric solutions] Ka of acetic acid 1.8×10−5, Ka of formic acid = 2.4×10−4
4.5 M
3.2 M
6.66 M
12.3 M
Nicotinic acid (Ka = 1.4 x 10−5) is represented by the formula HNic. For a solution which contains 0.10 mol of nicotinic acid per 2.0 litre of solution, the percent dissociation is:
4.2%
1.66%
3.33%
12.77%
- 1.4×10−4
- 1.4×10−5
- 3.7×10−4
- 2.8×10−4
A monoprotic acid in 1.00 M solution is 0.01% ionised. The dissociation constant of this acid is
1 X 10-8
1 X 10-4
1 X 10-6
1 X 10-5
The dissociation constant of two acids HA1 and HA2 are 3.14 × 10−4 and 1.96 × 10−5 respectively. The relative strength of the acids will be approximately
1:4
4:1
1:16
16:1
pH of two solutions :
I. 50 ml of 0.2 M~HCl + 50 ml of 0.2 M HA (Ka=1.0×10−5) and
II. 50 ml of 0.2 M HCl + 50 ml of 0.2 M NaA will be respectively
3 and 1
0.70 and 2.85
1 and 2.85
1 and 3
Ka=1.8×10−5 for CH3COOH
Take (1.34)2=1.8
- 3 mM HCOOH(Ka=6×10−4)
- 0.1 M CH3COONa
- 1.34 mM HCl
- 0.1 M CH3COOH
(Note: Degree of dissociation (α) of weak acid and weak base is << 1; degree of hydrolysis of salt << 1; [H+] represents the concentration of H+ ions)
LIST -ILIST-IIP. 10 mL of 0.1 M NaOH +20 mL of1. The value of [H+] does not0.1 M acetic acid diluted to 60 mLchange on dilutionQ. 20 mL of 0.1 M NaOH +20 mL of2. The value of [H+] changes to half0.1 M acetic acid diluted to 80 mLof its initial value on dilutionR. 20 mL of 0.1 M HCl + 20 mL of 0.13. The value of [H+] changes to twoM ammonia solution diluted to 80 mLtimes of its initial value on dilutionS. 10 mL saturated solution of Ni(OH)24. The value of [H+] changes to 1√2in equilibrium with excess solid Ni(OH)2times of its initial value on dilutionis diluted to 20 mL (solid Ni(OH)2is stillpresent after dilution).5. The value of [H+] changes to √2times of its initial value on dilution
Match each process given in LIST -I with one or more effect(s) in LIST -II. The correct option is
- P→4;Q→2;R→3;S→1
- P→4;Q→3;R→2;S→3
- P→1;Q→5;R→4;S→1
- P→1;Q→4;R→5;S→3