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Question

It has been found that the pH of a 0.01M solution of an organic acid is 4.15. Calculate the concentration of the anion, the ionization constant of the acid and its pKa. 


Solution

Let the organic acid be HA
HAH++A
Concentration of HA = 0.01 M pH
= 4.15 
log[H+]=4.15[H+]=7.08×105
Ka=[H+][A][HA]
Now,
[H+]=[A]=7.08×105[HA]=0.01
Then,
Ka=(7.08×105)(7.08×105)0.01Ka=5.01×107pKa=log Ka=log(5.01×107)pKa=6.3001


Chemistry
NCERT Textbook
Standard XI

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