Oxides of Xenon
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- Trigonal pyramidal
- Square planar
- V-shape
- See-saw
- 2
- 4
- 6
- 8
- XeO4 molecule is square planar.
- There are four pπ−dπ bonds.
- There are four sp3−p, σ bonds.
- XeO4 molecule is tetrahedral.
What do you understand by the term auto-protolysis of water? What is its significance?
For a reaction at 25∘C enthalpy change (△H) and entropy change (△S) are −11.7×103Jmol−1 and −105Jmol−1K−1 respectively. Find out whether this reaction is spontaneous or not?
Spontaneous
Non-spontaneous
- Enantiomers
- Daistereisomers
- Identical
- None of these
How are XeO3 and XeO4 prepared?
Reason: Oxygen forms pπ−pπ multiple bonds due to small size and small bond length but pπ−pπ bonding is not possible in sulphur.
- Assertion is wrong but reason is correct statement
- Both assertion and reason are wrong statements.
- Assertion is correct but reason is wrong statement
- Both assertion and reason are correct statements, and reason is the correct explanation of the assertion
- Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
- (i) and (ii)
- (ii) and (iii)
- (i) and (iii)
- None of these
XeF6+........⟶XeO3+HF
Complete the reaction
- 24H2O
- 3H2O
- 6H2O
- 12H2O
- XeF6
- XeOF4
- XeF4
- XeO2F2
- Only is formed
- Initially is formed which slowly gets oxidized to
- A mixture of both and is obtained
- No reaction
n-factor for Fe3O4 is :
The noble gases have closed-shell electronic configuration and are monoatomic gases used normal conditions. The low boiling points of the lighter noble gases are due to weak dispersion forces between the atoms and the absence of other interatomic interactions.
The direct reaction of xenon with fluorine leads to a series of compounds with oxidation number +2, +4 and +6. XeF4 reacts violently with water to give XeO3. The compounds of xenon exhibit rich stereochemistry and their geometries can be deduced considering the total number of electron pairs in the valence shell.
The structure of XeO3 is
linear
planar
pyramidal
T-shaped
- All of the above
- 0
- 1
- 2
- 3
- XeO4
- SF4
- XeF4
- CF4
- In (Ph3Si)2O, the Si-O-Si group is nearly linear
- Silanols such as (CH3)3SiOH are stronger protonic acids then their carbon analogs
- Trisilyl phosphine P(SiH3)3 is planar
- ClO−4 does not polymerise at all
Reason: Oxygen forms pπ−pπ multiple bonds due to small size and small bond length but pπ−pπ bonding is not possible in sulphur.
- Assertion is correct but reason is wrong statement
- Both assertion and reason are correct statements, but reason is not the correct explanation of the assertion.
- Assertion is wrong but reason is correct statement
- Both assertion and reason are wrong statements.
- Both assertion and reason are correct statements, and reason is the correct explanation of the assertion
- Interstitial compounds
- Hydrates
- Clathrates
- Picrates
- All of the above
- that there is a high activation energy barrier between oxidation state +6 to 0
- that standard emf is positive
- that ΔG∘=+ve
- that ΔG∘=−ve
Answer whether the above statement is true or false.
- True
- False
- Cu2I2 is formed
- CuI2 is formed
- Na2S2O3 is oxidised
- Evolved I2 is reduced
- NH3
- NO
- H2
- CO2
(A) 6XeF4 + 12H2O → 4Xe + 2XeO3 + ___(i)___ + ___(ii)___
(B) XeF6 + 3H2O → ___(iii)___ + 6HF
- (i) F2, (ii) H2O, (iii) XeOF4
- (i) 24HF, (ii) 3O2, (iii) XeO3
- (i) 2HF, (ii) 2H2O, (iii) XeO
- (i) HF, (ii) H2O, (iii) Xe2O3
Give the formula and describe the structure of a noble gas species which is isostructural with:
ICl−4
IBr−2
BrO−3