Planck's Quantum Hypothesis
Trending Questions
What is the number of photons of light with a wavelength of 4000 pm that provide 1 J of energy?
- 5p
- 3d
- 4f
- 6d
3 × 107
2 × 10-25
5 × 10-8
4 × 101
The wavelength of the radiation emitted, when a Hydrogen atom electron falls from infinity to the stationary state, would be:
Rydberg constant
Find energy of each of the photons which
(i) correspond to light of frequency 3× 1015 Hz.
(ii) have wavelength of 0.50 Å.
- Photons have both particle and wave nature
- Photons are waves
- Photons are straem of particles
- No such inference can be drawn from the given equation
Rest mass of a photon is _______.
State the postulates of Plancks quantum theory.
An X-ray tube is operated at . The shortest wavelength of the produced photon will be:
- 3.313×10−12 erg
- 3.313×10−13 erg
- 3.313×10−10 erg
- 3.313×10−11 erg
(1 nm = 10−9 m)
- Frequency(ν) =6.6×1014 Hz
- Wave number(~ν) =2.2×106 m−1
- None of the above
- Both (a) and (b)
- 22
- 20
- 14
- 28
- 3:5
- 10:3
- 6:2
- 2:1
(1 eV=1.6×10−19 J, hc=12423 eV oA)
- 2×1019
- 4×1018
- 5×1021
- 2×1021
Calculate the energy in corresponding to light of wavelength
- 211.6 pm
- 211.6π pm
- 52.9π pm
- 105.8 pm
AgClhv−→Ag (Gray)+12Cl2
If the heat of reaction for the decomposition of AgCl is 248 kJ mol−1. Find the wavelength needed to induce the desired process?
- 4.83×10−7 m
- 9.66×10−7 m
- 2.41×10−7 m
- 4.83×10−6 m
The maximum emission wavelength at temperature is . The maximum wavelength corresponding to temperature will be
- 4.125×103∘A
- 5.125×103∘A
- 7.125×103∘A
- 4.125×104∘A
(Take planck's constant h=6×10−34J s and speed of light c=3×108 m s−1)
- 6.21×103∘A
- 6.20×103 nm
- 4.41×103 nm
- 4.41×103∘A
In astronomical observations, signals observed from the distant stars are generally weak. If the photon detector receives a total of 3.15 × 10–18 J from the radiations of 600 nm, calculate the number of photons received by the detector.
How does quantum mechanics differ from classical mechanics?
- 2.72×1018
- 27.2×1018
- 0.272×1018
- 2.72×1016
How did plank explain the black body radiation?
- 0.216×10−18 J
- 0.216×10−17 J
- 0.216×10−20 J
- 0.216×10−19 J
How is heat transferred by radiation?
- 1:3
- 1:2
- 2:1
- 2:3
- 493 nm
- 4900 μm
- 4900 nm
- 493 m