Radioactive Series
Trending Questions
Q. In 4n + 2 series the number of total α, β particles emitted will be respectively?
- 6, 4
- 8, 5
- 8, 6
- 7, 4
Q. 95Am241 and 90Th234 belong respectively to:
- 4n and (4n +1) radioactive disintegration series
- (4n + 1) and (4n + 2) radioactive disintegration series
- (4n + 1) and (4n + 3) radioactive disintegration series
- (4n +1) and 4n radioactive disintegration series
Q. The element 90Th232 belongs to thorium series. Which of the following will act as the end product of the series
- 82Pb208
- 82Bi209
- 82Pb206
- 82Pb207
Q. 95Am241 and 90Th234 belong respectively to:
- 4n and (4n +1) radioactive disintegration series
- (4n + 1) and (4n + 2) radioactive disintegration series
- (4n + 1) and (4n + 3) radioactive disintegration series
- (4n +1) and 4n radioactive disintegration series
Q. At any given time a piece of radioactive material (t1/2=30days) contains 1012 atoms. Calculate the activity of the sample in dps?
- 3.67×105dps
- 1.67×105dps
- 2.67×105dps
- 4.67×105dps
Q. Radioactivity of naptunium stops when it is converted to
- Th
- Rn
- Pb
- Bi
Q. Series Starts with Ends with
4n+1 24194Pu 20983Bi
If true enter 1, else enter 0.
4n+1 24194Pu 20983Bi
If true enter 1, else enter 0.
Q. In the given radioactive disintegration series,
23290Th→20882Pb
Calculate the value of (n+2) where value of n is number of isobars formed in this series emission of β − particles.
23290Th→20882Pb
Calculate the value of (n+2) where value of n is number of isobars formed in this series emission of β − particles.
Q. 23592U decays with emission of α and β− particles to form ultimately 20782Pb. How many α− and β−particles are emitted per atom of Pb produced?
Q. The element 23290Th belongs to 4n series which will be the end product of this series:
- 20882Bi
- 20983Bi
- 20982Bi
- 20782Bi
Q. After the emission of a β-particle followed by α-particle from 21483Bi, the number of neutrons in the atom is:
- 129
- 130
- 128
- 127
Q. 23490Th disintegrates to give 20682Pb as the final product. The number of α- and β-particles are emitted during the process:
- 7α and 6β
- 7α and 5β
- None of these
- 9α and 6β
Q. The half-life for the radioactive decay of 14C is 5730, yr. An architect contained wood that had only 80% of the 14C found in a living tree. Estimate the age of the sample.
Q. During β^-decay, the mass of atomic nucleus :
- decreases by 1 unit
- increases by 1 unit
- decreases by 2 units
- remains unaffected
Q. The end product of (4n+2) radioactive disintegration series is
- 82Pb208
- 82Pb206
- 82Pb207
- 83Bi210
Q. A radioactive substance (parent) decays to it's daughter element, the age of radioactive substance (t) is related to the daughter (d) parent (p) ratio by the equation :
- t=1λln(1+pd)
- t=1λln(pd)
- t=1λln(1+dp)
- t=1λln(dp)
Q. 23290Th disintegrates to 20882Pb. How many of β-particles are evolved?
Q. The element 90Th232 belongs to thorium series. Which of the following will act as the end product of the series
- 82Pb208
- 82Bi209
- 82Pb206
- 82Pb207
Q. In the given radioactive disintegration series,
23290Th→20882Pb
Calculate the value of (n+2) where value of n is number of isobars formed in this series emission of β − particles.
23290Th→20882Pb
Calculate the value of (n+2) where value of n is number of isobars formed in this series emission of β − particles.
Q. Which of the following transmutations demonstrate(s) beta decay?
i. Bu−212→Po−212
ii. Pb−212→Bi−212
iii. Ra−228→Ac−228
i. Bu−212→Po−212
ii. Pb−212→Bi−212
iii. Ra−228→Ac−228
- i only
- ii and iii only
- ii only
- i and ii only
- i, ii and iii
Q.
Thorium (90) formed from emission of α-particle from uranium (92, group IIIB) has been placed in group IIIB.
- True
- False
Q. A radioactive substance has a constant activity of 2000 disintegration/minute. The material is separated into two fractions, one of which has an initial activity of 1000 disintegrations per second while the other fraction decays with t1/2=24 hours. The total activity in both samples after 48 hours of separation is
- 2000
- 1250
- 1000
- 1500
Q. Radioactivity of naptunium stops when it is converted to
- Bi
- Rn
- Th
- Pb
Q. In 4n + 2 series the number of total α, β particles emitted will be respectively?
- 6, 4
- 8, 5
- 8, 6
- 7, 4
Q. The element 23290Th belongs to 4n series which will be the end product of this series:
- 20983Bi
- 20882Bi
- 20982Bi
- 20782Bi
Q. How many neutrons are emitted in the reaction?
236U⟶141Ba+92Kr
236U⟶141Ba+92Kr
- 3
- 2
- 5
- 7
Q. 89Ac231 gives 82Pb207 after emission of some α and β -particles. The number of such α and β -particles are respectively:
- 5, 7
- 6, 5
- 7, 5
- 5, 6
Q.
Thorium disintegration series is known as:
- (4n) series
- (4n + 2) series
- (4n + 3) series
- (4n + 1) series
Q. In 4n + 2 series the number of total α, β particles emitted will be respectively?
- 6, 4
- 8, 5
- 8, 6
- 7, 4
Q. The number of α and β particles lost when 23892U changes to 20682Pb are:
- 8α , 6β
- 6α , 8β
- 6α , 6β
- 8α , 8β