Reduction of Carboxylic Acids

Q.

1. H₂ / Pt

2. H₂ / Pd - BaSO₄

3. Cr₂O₇^-2 / H⁺

4. Zn - Hg / HCl

Q.

When CH₂ = CH - COOH is reduced with LiAlH₄ , the compound formed is

1. CH₃CH₂CH₂OH

2. CH₃CH₂CHO

3. CH₃CH₂COOH

4. CH₂ = CH - CH₂OH

Q.

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Q.

Which of the given sequences helps convert pentane-1, 5-dioic acid to heptane-1, 7-dioic acid?

1. 1: $NaB{H}_4$ in acid;
   2: $PB{r}_3$;
   3: $\text{KCN}\text{followed by}{H}_3{O}^{+}$

2. None of the above

3. 1: $\text{Na-Hg}\text{amalgam}$;
   2: $PB{r}_3$;
   3: $\text{KCN}\text{followed by}{H}_3{O}^{+}$

4. 1: $LiAl{H}_4$ followed by work up;
   2: $PB{r}_3$;
   3: $\text{KCN}\text{followed by}{H}_3{O}^{+}$

Q. $\mathrm{Ph}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}\stackrel{\mathrm{PCC}}{\to }$

1. $\mathrm{Ph}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{CH}=O$
2. $\mathrm{Ph}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{COOH}$
3. $\mathrm{Ph}-{\mathrm{CH}}_2-\mathrm{CO}-{\mathrm{CH}}_3$
4. $\mathrm{Ph}-{\mathrm{CH}}_2-\mathrm{CH}=O+{\mathrm{CH}}_3\mathrm{OH}$

Q. $\mathrm{Ph}-\mathrm{CO}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{COOH}\stackrel{{\mathrm{BH}}_3}{\to }\mathrm{Ph}-\mathrm{CO}-{\mathrm{CH}}_2-{\mathrm{CH}}_2-{\mathrm{CH}}_2-\mathrm{OH}$In the above reaction the reagent acts as a:

1. Chemoselective reducing agent
2. Stereoselective reducing agent
3. Stereospecific reducing agent
4. Rigeoselective reducing agent

Q. In reduction of carboxylic acids $LiAl{H}_4$ acts as $H^{-}$ donar.

1. False
2. True

Q. Acid can be reduced by:

1. $HI/P$
2. $LiAl{H}_4$
3. $C{H}_{3}Li$
4. All

Q. Reagent(s) which can be used to bring about the following transformation is/are:

1. $LiAl{H}_{4}in(C_2{H}_5{)}_{2}O$
2. $B{H}_{3}inTHF$
3. $NaB{H}_{4}in{C}_2{H}_{5}OH$
4. $RaneyNi/H_{2}inTHF$

Q. Treatment of benzene with $CO/HCl$ in the presence of anhydrous $AlC{l}_3/CuCl$ followed by reaction with $A{c}_{2}O/NaOAc$ gives compound X as the major product. Compound X upon reaction with $B{r}_2/N{a}_{2}C{O}_3$, followed by heating at 473 K with moist $KOH$ furnishes Y as the major product. Reaction of X with $H_2/Pd-C,$followed by $H_{3}P{O}_4$ treatment gives Z as the major product.
The compound Z is:

1. 
2. 
3. 
4.