The reaction of $C_{6} H_{5} C H = C H C H O$ with $L i A l H_{4}$ gives,

C_{6} H_{5} C H_{2} C H_{2} C H_{2} O H

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C_{6} H_{5} C H = C H C H_{2} O H

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C_{6} H_{5} C H_{2} C H_{2} C H O

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C_{6} H_{5} C H_{2} C H O H C H_{3}

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Solution

The correct option is A $C_{6} H_{5} C H_{2} C H_{2} C H_{2} O H$
$L i A l H_{4}$ will reduce aldehydes to primary alcohols.
$L i A l H_{4}$ does not reduce alkene, but when the alkene is in conjugation with aldehyde or phenyl group, then alkene also get reduced.
Hence, Both alkene and aldehyde groups are reduced.
Thus, option (a) is correct.

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