Salt of Weak Acid and Weak Base
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Q. The ionization constant of ammonium hydroxide is 1.77×10−5 at 298 K. Hydrolysis constant of ammonium chloride is:
- 5.56×10−12
- 5.65×10−10
- 6.50×10−12
- 5.65×10−13
Q. When 10 mL of 0.1 M acetic acid (pKa=5.0) is titrated against 10 mL of 0.1 M ammonia solution (pKb=5.0) the equivalence point occurs at pH of:
- 5
- 6
- 7
- 9
Q.
Calculate the degree of hydrolysis ammonium acetate. Given Ka = 1.75 × 10−5 ; Kb = 1.80 × 10−5.
Q. The dissociation constants for aniline, acetic acid and water at 25∘ C are 4×10−10, 2×10−5 and 10−14 respectively. Calculate degree of hydrolysis of aniline acetate in a decinormal solution.
- 0.15
- 0.45
- 0.53
- 0.35
Q. Which of the following describes the correct relation for hydrolysis constant (Kh) for a salt of weak acid and weak base at 25∘C ?
- Kh=KwKa×Kb
- Kh=KaKw×Kb
- Kh=Ka×KbKw
- Kb=KhKa×Kw
Q.
of an aqueous solution of in the acidic medium completely reacted with of aqueous . The molarity of solution is .(Round off to the Nearest Integer).
Q. Calculate the degree of hydrolysis (h) of a salt of aniline and acetic acid in 0.1 M solution at 25∘C
Given :
Ka for CH3COOH is 1.8×10−5
Kb for aniline is 4.6×10−10
Given :
Ka for CH3COOH is 1.8×10−5
Kb for aniline is 4.6×10−10
- 0.996
- 0.85
- 0.235
- 0.523
Q. Which of the following statement(s) is/are correct for a salt of weak acid and weak base in an aqueous solution at 25∘C.
Here, Ka is the dissociation constant for a weak acid and Kb is the dissociation constant for a weak base.
Here, Ka is the dissociation constant for a weak acid and Kb is the dissociation constant for a weak base.
- If Ka>Kb then the solution is neutral.
- If Ka<Kb then the solution is acidic in nature.
- If Ka>Kb then the solution is acidic in nature.
- If Ka<Kb then the solution is alkaline in nature.
Q. pka of acetic acid and pKb of ammonium hydroxide are 4.76 and 4.75 respectively. Calculate the pH of ammonium acetate solution.
- 6.02
- 7.005
- 8
- 5.602
Q. In order to prepare a buffer solution of pH 5.74, sodium acetate is added to acetic acid. If the concentration of acetic acid in the buffer is 1.0 M, the concentration of sodium acetate in the buffer is ______M. (Round off to the Nearest Integer).
[Given: pKa (acetic acid) = 4.74]
[Given: pKa (acetic acid) = 4.74]
Q. pOH=7–0.5pKa+0.5pKb is true for an aqueous solution that has which pair of cations and anions amongst the following?
- C6H5NH+3, CH3COO−
- NH+4, F−
- Na+, CH3COO−
- NH+4, Cl−
Q. Ammonium acetate which is 0.01 M, is hydrolysed to 0.001 M concentration. Calculate the change in pH in 0.001 M solution, if initially pH=pKa.
log 9=0.354, log 3=0.477
log 9=0.354, log 3=0.477
- -1
- 1
- 2
- -2
Q. Read the assertion and reason carefully to mark the correct option out of the options given below:
Assertion: Nitrating mixture used for carrying our nitration of benzene consists of conc.HNO3+conc.H2SO4.
Reason :In presence of H2SO4, HNO3 acts as a base and produces NO+2ions.
Assertion: Nitrating mixture used for carrying our nitration of benzene consists of conc.HNO3+conc.H2SO4.
Reason :In presence of H2SO4, HNO3 acts as a base and produces NO+2ions.
- If both assertion and reason are true and the reason is the correct explanation of the assertion.
- If assertion is true but reason is false.
- If the assertion and reason both are false.
- If both assertion and reason are true but reason is not the correct explanation of the assertion.
Q. Which of the following describes the correct relation for pOH for an aqueous salt solution of weak acid and weak base at 25∘C ?
- pOH=14−12(pKa−pKb)
- pOH=7+12(pKa−pKb)
- pOH=7−12(pKa−pKb)
- pOH=14+12(pKa−pKb)
Q.
Relation between above compounds is:
Relation between above compounds is:
- Position isomers
- Chain isomers
- Identical
- Functional isomers
Q. When 10 mL of 0.1 M acetic acid (pKa=5.0) is titrated against 10 mL of 0.1 M ammonia solution (pKb=5.0) the equivalence point occurs at pH of:
- 5
- 6
- 7
- 9
Q. Which of the following statement is correct regarding an eqiumolar solution of a weak acid CH3COOH and a weak base NH4OH at 25∘C ?
- Higher the concentration of CH3COOH, lesser is the pH value.
- Higher the concentration of NH4OH, higher is the pH value.
- pH does not depend on the concentration of CH3COONH4.
- None of the above
Q. When 10 mL of 0.1 M acetic acid (pKa=5.0) is titrated against 10 mL of 0.1 M ammonia solution (pKb=5.0), the equivalence point occurs at pH:
- 9.0
- 6.0
- 7.0
- 5.0
Q. pKa of a weak acid (HA) and pKb of a weak base (BOH) are 3.2 and 3.4, respectively. The pH of their salt (AB) solution is :
- 7.0
- 7.2
- 1.0
- 6.9
Q. 5.0mL of 0.1MNaOH solution is added to 50mL of the 0.1M acetic acid solution. Calculate the pH of the resulting acetic acid solution.
(Ka=1.8×10−5)
Q. In a solution of NaHCO3 , in amphiprotic anion can undergo ionization to form H+ ion and hydrolysis to form OH− ion.
HCO−3+H2Oionization⇋CO2−3+H3O+
HCO−3+H2Ohydrolysis⇋H2CO−3+OH− to calculate pH, suitable approximation is :
HCO−3+H2Oionization⇋CO2−3+H3O+
HCO−3+H2Ohydrolysis⇋H2CO−3+OH− to calculate pH, suitable approximation is :
- [CO2−3]=[H2CO3]
- neither 'A' nore 'B'
- Degree of ionization = degree of hydrolysis
- both (A) and (B)
Q. Match the column I with column II and mark the appropriate choice.
Column I | Column II |
(A) CH3COONa | (i) Almost neutral, pH > 7 or < 7 |
(B) NH4Cl | (ii) Acidic, pH < 7 |
(C) NaNO3 | (iii) Alkaline, pH > 7 |
(D) CH3COONH4 | (iv) Neutral, pH = 7 |
- (A) - (i) ; (B) - (ii) ; (C) - (iii) ; (D) - (iv)
- (A) - (iii) ; (B) - (ii) ; (C) - (iv) ; (D) - (i)
- (A) - (ii) ; (B) - (iii) ; (C) - (iv) ; (D) - (i)
- (A) - (iv) ; (B) - (i) ; (C) - (iii) ; (D) - (ii)
Q.
If the molecular formula of compound E is CxHyOz. Then, the value of y−x−z is:
If the molecular formula of compound E is CxHyOz. Then, the value of y−x−z is:
Q. The dissociation constants for aniline, acetic acid and water at 25∘ C are 4×10−10, 2×10−5 and 10−14 respectively. Calculate degree of hydrolysis of aniline acetate in a decinormal solution.
- 0.53
- 0.15
- 0.35
- 0.45
Q. Which of the following statement is correct regarding an eqiumolar solution of a weak acid CH3COOH and a weak base NH4OH at 25∘C ?
- Higher the concentration of CH3COOH, lesser is the pH value.
- Higher the concentration of NH4OH, higher is the pH value.
- pH does not depend on the concentration of CH3COONH4.
- None of the above
Q. What will be the pH of an aqueous solution of 1.0 M ammonium formate?
Given: pKa=3.8 and pKb=4.8.
- 7.5
- 3.4
- 6.5
- 10.2
Q. What will be the pH of 0.1 M CH3COONH4? Dissociation constants of CH3COOH and NH4OH are Ka=1.8×10−5 and Kb=1.8×10−5 respectively.
Q. The ratio of volumes of CH3COOH (0.1 N) to CH3COONa (0.1 N) required to prepare a buffer solution of pH 5.74 is:
(Given pKa of CH3COOH is 4.74)
- 1 : 5
- 1 : 10
- 10 : 1
- 5 : 1
Q. The solution of a salt of a weak acid and weak base will have pH: (Kb=1×10−6 and Ka=1×10−4)
- 7.0
- 8.0
- 6
- 4.0
Q.
The degree of hydrolysis of ammonium acetate is related to its hydrolysis constant by the expression
a = Kh(1+Kh)
a = Kh(1+Kh2)
a = √Kh(1+√Kh)
a = √Kh(1+Kh)