Van der Waal's Forces
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Q.
The degree of freedom for tri-atomic gas is
Q. At high pressure, van der Waal's equation for one mole of the gas becomes:
- PV=RT+aV
- PV=RT−aV
- PV=RT
- PV=RT+Pb
Q.
A cylinder containing an ideal gas is in thermal equilibrium with a large volume of aqueous solution of ethylene glycol at its freezing point. If the stoppers and (as shown in the figure) suddenly withdrawn, the volume of the gas in after equilibrium is achieved will be:
(Given, )
Q. The constant 'a' in van der Waals' equation is maximum in:
- He
- O2
- NH3
- H2
Q.
What are dipole-dipole forces?
Q. For compressibility factor, Z, which of the following is /are correct?
- For most of the real gases Z decreases with P at the lower pressure
- For most of the real gases Z increases with P at the higher pressure
- All of the above statements are correct
- For H2 (g) and He(g) Z increases with P at all the pressure & at room temperature
Q. Arrange the following in the decreasing order of their van der Waals constant ′a′ values:
H2O, CO2, Ar
H2O, CO2, Ar
- Ar>H2O>CO2
- H2O>CO2>Ar
- Ar=H2O=CO2
- H2O>Ar>CO2
Q. The correction factor ‘a’ to the ideal gas equation corresponds to:
- Volume of the gas molecules
- Electric field present between the gas molecules
- Density of the gas molecules
- Forces of attraction between the gas molecules
Q. The compressibility factor for a real gas is expressed by, z=1+BPRT. The value of B at 500 K and 600 bar is 0.0169 L/mol. Find the molar volume of the gas
- 0.1 L
- 9×10−5L
- 8.62×10−2L/mol
- 1.65 L
Q. At high temperature and low pressure, the van der Waals' equation is reduced to:
- (P+aV2)V=RT
- P(V−b)=RT
- (P+aV2)(V−b)=RT
- PV=RT
Q. Calculate the pressure exerted by one mole of CO2 gas at 273 K if the van der Waal's constant, a=3.592 dm6 atm mol−2. Assume that the volume occupied by CO2 molecules is negligible.
- 0.9922 atm
- 1.9922 atm
- 9.9222 atm
- 0.1922 atm
Q. 'a' and 'b' are van der Waals' constants for gases. Chlorine is more easily liquefied than ethane because
- a and b for Cl2>a and b for C2H6
- a and b for Cl2<a and b for C2H6
- a for Cl2>a for C2H6 but b for Cl2>b for C2H6
- a for Cl2>a for C2H6 but b for Cl2<b for C2H6
Q. The van der Waals' equation for 0.5 mol gas is:
- (P+a4V2)(V−b2)=3RT2
- (P+a4V2)(2V−b)=RT
- (P+a4V2)(2V−4b)=RT
- (P+a4V2)=2RT2(V−b)
Q.
The term that corrects for the attractive forces present in a real gas in the Van der Waals equation is _____.
Q. For one mole of a gas, under critical conditions, the compressibility factor is:
- 83
- 1
- 14
- 38
Q. Which of the following has the highest melting point?
- F2
- Cl2
- Br2
- I2
Q. The reduced temperature for benzene is 0.7277 and its reduced volume is 0.40. Calculate the reduced pressure of benzene.
- 40.358
- 30.358
- 20.358
- 10.358
Q.
Define London forces
Q. Find the temperature (in K) at which 3 moles of SO2 will occupy a volume of 10 L at a pressure of 15 atm.
[ a=6.71 atm litre2 mol−2; b=0.0564 litre mol−1]
[ a=6.71 atm litre2 mol−2; b=0.0564 litre mol−1]
Q. In van der Waals' equation of state for a non-ideal gas, the term that accounts for intermolecular forces is:
- RT
- b
- aV2
- (RT)−1
Q. Calculate pressure exerted by 1 mole of a van der Waal gas at a temperature of 80.0821K in a 12 L container, if the volume of the molecule is assumed to be negligible and van der Waal's constant a=2 atm L2 mol−2
Q. Statement–1: The value of the van der Waals constant ‘a’ is larger for NH3 than PH3.
Statement–2: Hydrogen bonding is present in NH3
Statement–2: Hydrogen bonding is present in NH3
- Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1
- Statement-1 is True, Statement-2 is False
- Statement-1 is False, Statement-2 is True
Q.
What is an ideal gas? Explain.
Q. Calculate the temperature of the gas (in kelvin) if it obeys van der Waals' equation from the following data. A flask of 2.5 L contains 10 mol of a gas under 50 atm. Given (a=5.46 atm L2 mol−2, b=0.031 L mol−1).
Q. Read the following statement and explanation and choose the correct option.
Assertion : The value of van der Waals' constant 'a' is larger for ammonia than for nitrogen.
Reason : Hydrogen bonding is present in ammonia.
Assertion : The value of van der Waals' constant 'a' is larger for ammonia than for nitrogen.
Reason : Hydrogen bonding is present in ammonia.
- Both assertion and reason are correct, and reason is the correct explantion of the assertion.
- Both assertion and reason are correct.
- Both assertion and reason are correct, but reason is not the correct explantion of the assertion.
- Both assertion and reason are incorrect.
Q. 36. What is meant by virial coefficient of real gas?
Q.
The weakest interaction among the following is _____.
Metallic
Ionic
Van der Waal
Covalent
Q. Which one of the following has the highest boiling point?
- Kr
- Xe
- He
- Ne
Q. 14(L)Consider the following statements:I The pressure of moist gas is more than that ofdry gas under identical condition.Critical temperature is the highest temperatureat which liquid and vapour coexistAt constant temperature, PV vs P (Ppressure and V = volume) plot for real gaseswill be a straight line at very high pressure.28. 10The correct statement(s) is/are(2) Only \vert & II)(1) Only II & IlII)(3) Only I & Il
Q. Calculate the pressure exerted by one mole of CO2 gas at 273 K if the van der Waal's constant, a=3.592 dm6 atm mol−2. Assume that the volume occupied by CO2 molecules is negligible.
- 0.9922 atm
- 1.9922 atm
- 9.9222 atm
- 0.1922 atm