Bijective Function
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Then which of the following statements is(are) TRUE ?
- The equation f(x)−3cos3x=0 has at least one solution in (0, π3)
- The equation f(x)−3sin3x=−6π has at least one solution in (0, π3)
- limx→0xx∫0f(t)dt1−ex2=−1
- limx→0sinxx∫0f(t)dtx2=−1
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Check the injectivity and surjectivity of the following functions:
(i)f:N→N given by f(x)=x2
(ii)f:Z→Z given by f(x)=x2
(ii)f:Z→Z given by f(x)=x2
(iv)f:N→N given by f(x)=x3
(v)f:Z→Z given by f(x)=x3
f:R→R, f(x)=x|x| is
one-one but not onto
onto but not one-one
Both one-one and onto
neither one-one nor onto
- A=(−∞, 3] and B=(−∞, 1]
- A=[3, ∞) and B=(−∞, 1]
- A=(−∞, −3] and B=(−∞, −1]
- A=[−3, ∞) and B=[1, ∞)
- a one-one function
- a many-one function
- an into function
- an onto function
The greatest value of on is
(i) f(x)=−|x| (ii) f(x)=√9−x2
Is The Modulus of A Complex Number Always Positive?
If . Then,
Statement-I: The set .
Statement-II: is a bijection.
Statement-I is correct and Statement-II is correct; Statement-II is a correct explanation for Statement-I.
Statement-I is correct and Statement-II is correct; Statement-II is not a correct explanation for Statement-I.
Statement-I is correct and Statement-II is incorrect;
Statement-I is incorrect and Statement-II is incorrect;
If fog and gof are defined, then which of the following is/are correct
- fog is an even function
- fog is an odd function
- gof is an odd function
- gof is an even function
Let f:X→Y be an invertible function. Show that the inverse of f−1 is f i.e., (f−1)−1=f.
- f:R→[0, ∞) defined as f(x)=e sgn(x)
- f:R→R defined by f(x)=[x]+cos(π[x]) where [.] denotes the greatest integer function
- f:R→R defined as f(x)=min{x+2, −2x+4}
- f:[3, 4]→[4, 6] defined by f(x)=|x−1|+|x−2|+|x+3|+|x−4|
- bijective function
- injective but not surjective
- surjective but not injective
- neither injective nor surjective
If is differentiable and , then
- g∘f is bijective but f is not injective
- g∘f is injective and g is injective
- g∘f is injective but g is not bijective
- g∘f is surjective and g is surjective
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Let A =R -{3}, B=R -{1}. If f:A→B be defined by f(x)=x−2x−3, ∀x∈A. Then, show that f is bijective.
What are transitive relations?
Let and . Then the number of onto functions from to is?
- (−∞, −1]
- [−1, 3]
- (−∞, 3]
- [3, ∞)
Consider f:R+→[−5, ∞) given by f(x)=9x2+6x−5 show that f is ivnertible with f−1(y)=((√y+6)−13)
If and respectively denote the moduli of the complex numbers and , then the correct one, among the following is:
- (b−a)a<lnba<(b−a)b
- (b−a)b<lnba<(a−b)b
- (b−a)b<lnba<(b−a)a
- (b−a)a<lnba<(a−b)a
Describe Absolute Value Function