Centroid
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Let be in arithmetic progression. Let the centroid of the triangle with vertices and be . If are the roots of the equation , then the value of is:
- (1, 73)
- (13, 53)
- (13, 1)
- (13, 2)
- (1136, 4)
- (4, 1136)
- (3, 511)
- (511, 3)
Let , , be the vertices of a . If the centroid of this triangle moves on the line , then the locus of the vertex is the line.
The centroid of an equilateral triangle is (0, 0). If two vertices of the triangle lie on x + y = 2√2 , then one of them will have its coordinates as
- (√2+√6, √2−√6)
- (√2+√3, √2−√3)
- (√2+√5, √2−√5)
- (√2+√6, √2+√6)
- (3x−1)2+(3y)2=a2−b2
- (3x−1)2+(3y)2=a2+b2
- (3x+1)2+(3y)2=a2+b2
- (3x+1)2+(3y)2=a2−b2
- parallel to x-axis
- with slope 32
- parallel to y-axis
- with slope 23
- (43, 3)
- (3, 23)
- (3, 43)
- (43, 23)
The centroid of a triangle is (2, 7) and two of its vertices are (4, 8) and (−2, 6). The third vertex is
(7, 4)
(7, 7)
(0, 0)
(4, 7)
- (−1, 3+√3) and (−1, 3−√3)
- (1, 3+√3) and (1, 3−√3)
- (2, 3+√3) and (2, 3−√3)
- (1, 3+2√3) and (1, 3−2√3)
If the points (1, -1), (2, -1) and (4, -3) are the mid-points of the sides of a triangle, then write the coordinates of its centroid.
Find the direction cosines of the sides of the triangle whose vertices are (3, 5, -4), (-1, 1, 2) and (-5, -5, -2).
- (−9, −7)
- (−9, −6)
- (9, 7)
- (7, 6)
(1) The graph of y passes through the point (1, 6).
(2) 1p, 1q, 1r form an arithmetic progression.
(3) p, r, q are in geometric progression.
Which of the following options is/are correct?
- Sum of the roots of y=0 is −4.
- Product of the roots of y=0 is −2.
- There exist 2 real and distinct roots of y=0
- There exist 2 real and equal roots of y=0.
- 2y-3x-25=0
- 3x+5y+25=0
- 2x-5y+25=0
- 2x-5y-25=0
- The centroid of △A2B2C2 is (3, 2)
- The centroid of △A3B3C3 is (3, 2)
- Area (△A2B2C2)Area (△ABC)=116
- Area (△A3B3C3)Area (△ABC)=116
- (1, 2)
- (2, 3)
- (1, −1)
- (2, −1)
- (1, 2)
- (2, 3)
- (3, 4)
- (3, 5)
- Orthocentre ≡(5, 7)
- Orthocentre ≡(4, 8)
- Circumcentre ≡(3, 10)
- Centroid ≡(103, 283)
The vertices of a triangle are (6, 0) (0, 6) and (6, 6). The distance between its circumcentre and centroid is
2√2
√2
2
1
How do you find the terminal point on the unit circle determined by the given value of ?
- Area (â–³A2B2C2)Area (â–³ABC)=116
- Area (â–³A3B3C3)Area (â–³ABC)=116
- The centroid of â–³A3B3C3 is (3, 2)
- The centroid of â–³A2B2C2 is (3, 2)
- 2
- √6
- 4
- 2√5
- (3x−1)2+(3y)2=a2−b2
- (3x−1)2+(3y)2=a2+b2
- (3x+1)2+(3y)2=a2+b2
- (3x+1)2+(3y)2=a2−b2
- (1, 2)
- (2, −1)
- (1, −1)
- (2, 3)
Find the coordinates of the incentre and centroid of the triangle whose sides have the equations 3x−4y=0, 12y+5x=0 and y−15=0.
- √3/4
- √3/2
- √3
- None of these
- (−2, −2)
- (2, −2)
- (−2, 2)
- (2, 2)