Chord with a Given Mid Point : Ellipse
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- a circle
- a parabola
- an ellipse
- a hyperbola
(where [.] denotes greatest integer function)
- x2a2+y2b2=exa
- None of the above
- x2a2−y2b2=exa
- x2+y2=a2+b2
Find the equation of the chord of the ellipse 4x2+25y2=100 whose middle point is (1, 1).
4x + 25y = 29
5x +25y = 30
25x + 4y = 29
25x + 5y = 30
If the eccentricity of the hyperbola is and is a focal chord of the hyperbola, then the length of the transverse axis is
- x−y=0
- x+y=0
- x−7y=0
- 7x−y=0
- 38
- √3
- 1√3
- 83
On the ellipse then find the point the distance from which to our focus is four times the distance to the other focus
The locus of the midpoint of a chord of the circle which subtends a right angle at the origin is
What is the equation of chord of the ellipse x2a2+y2b2=1 whose middle point is (x1, y1) ? You are given. T=xx1a2+yy1b2−1andS1x21a2+y21b2−1
T + S1=0
T = S1
T + S1= 1
T + 1= S1
- 16x – 75y = 418
- 75x - 16y = 418
- 25x - 4y = 400
- None of these
- 83
- √3
- 1√3
- 38
Find the equation of the chord of the ellipse 4x2+25y2=100 whose middle point is (1, 1).
4x +25y =29
5x+25y=30
25x +4y=29
25x +5y =30
Find the equation of the chord of the ellipse 4x2+25y2=100 whose middle point is (1, 1).
4x +25y =29
5x+25y=30
25x +4y=29
25x +5y =30
- x2a2+y2b2=exa
- x2a2−y2b2=exa
- x2+y2=a2+b2
- None of the above
- 83
- √3
- 1√3
- 38
What is the equation of chord of the ellipse x2a2+y2b2=1 whose middle point is (x1, y1) ? You are given. T=xx1a2+yy1b2−1andS1x21a2+y21b2−1
T+S1=0
T=S1
T+S1=1
T+1=S1
- x2+y2+4x+52=0
- x2+y2−5x+92=0
- x2+y2+5x+7=0
- x2+y2+2x+5=0
- x2+y2=hx+ky
- x2−y2=hx+ky
- x2+y2=hx−ky
- x2−y2=hx−ky
- a circle
- a parabola
- an ellipse
- a hyperbola
- 5√2
- 4√50
- 2√5
- 4√5
- 16x – 75y = 418
- 75x - 16y = 418
- 25x - 4y = 400
- None of these
(where [.] denotes greatest integer function)
- 16x – 75y = 418
- 75x - 16y = 418
- 25x - 4y = 400
- None of these
- 3x+4y−1−0
- 4x+3y+1=0
- 4x−3y−1=0
- 3x−4y+1=0