Differentiabilty
Trending Questions
Q. If f(x)={21x, for x≠0, 3, for x=0, then
- f (x) is continuous at x = 0
- limx→0+f(x)=0
- limx→0−f(x)=∞
- None of these
Q.
If f(x)=|x|3 , show that f′′(x) exists for all real x and find it.
Q. Let f(x)={x2+k, whenx≥0−x2−k, whenx<0. If the function f (x) be continuous at x = 0, then k =
- 0
- 1
- 2
- -2
Q. If f(x)={|x−a|x−a, when x≠a1, when x=a , then
- f(x) is continuous at x = a
- f(x) is discontinuous at x = a
- limx→af(x)=1
- None of these
Q. If f(x)=⎧⎪
⎪
⎪⎨⎪
⎪
⎪⎩2−(128−6x)17(4x+16)14−2, x≠0k , x=0 is continuous at x=0 and g is a function with the property that g(x+y)=g(x)+g(y)+xy and limh→0g(h)h=28f(0)
- g is a differentiable function
- g(x)=3x+x22+1
- g(x)=3x+x22
- g(x)=3+x
Q. Let f(x)=⎧⎨⎩x3+x2−16x+20(x−2)2, if x≠2 k, if x=2 f f(x)be continuous for all x, then k =
- 7
- -7
- ±7
- None of these
Q. If f(x)={min{x, x2}, x≥0min{2x, x2−1}, x<0 then the number of points where f(x) is non-differentiable in [−2, 2] is
Q. If f(x)=⎧⎪⎨⎪⎩ax2−b, when0≤x<12, whenx=1x+1, when1<x≤2 is continuous at x = 1, then the most suitable value of a, b are
- a = 2, b = 0
- a = 1, b = -1
- a = 4, b = 2
- All the above
Q. Each of the following function is defined to be zero at x = 0
f1(x)=x2 sgn (x)
f2(x)=∫x0t2 sin (1t)dt
f3(x)=x−13 |sin x|
f4(x)=x3[−x]
[where sgn(x) denotes signum function and [.] denotes greatest integer function]
List - IList - IIIThe function f1(P)continuous but not differentiable at x = 0IIThe function f2 is (Q)first derivative exists at x = 0 but second derivative does not existIIIThe function f3 is(R)second derivative exists at x = 0, but it is not continuous thereIVThe function f4 is (S)second derivative exists at x = 0and is continuous at x = 0.
Which of the following is the only CORRECT combination?
f1(x)=x2 sgn (x)
f2(x)=∫x0t2 sin (1t)dt
f3(x)=x−13 |sin x|
f4(x)=x3[−x]
[where sgn(x) denotes signum function and [.] denotes greatest integer function]
List - IList - IIIThe function f1(P)continuous but not differentiable at x = 0IIThe function f2 is (Q)first derivative exists at x = 0 but second derivative does not existIIIThe function f3 is(R)second derivative exists at x = 0, but it is not continuous thereIVThe function f4 is (S)second derivative exists at x = 0and is continuous at x = 0.
Which of the following is the only CORRECT combination?
- (I), (P)
- (II), (R)
- (III), (S)
- (IV), (Q)
Q. If f(x)={min{x, x2}, x≥0min{2x, x2−1}, x<0 then the number of points where f(x) is non-differentiable in [−2, 2] is
Q. If the function f(x)=⎧⎪⎨⎪⎩x2−(A+2)x+Ax−2for x≠22for x=2 is
continuous at x=2 , then
continuous at x=2 , then
- A=0
- A=−1
- A=1
- A=2
Q. The minimum values of f(x)=2(x2−3)3+27
- 4
- 16
- 227
- 1
Q. Let f:R→R be defined as f(x)=⎧⎪⎨⎪⎩max{−x, x+2}, x<02, 0≤x<13−x, x≥1. Then
- f(x) is continuous for all x∈R
- f′(x)>0 for −1<x<0
- f(x) is non-differentiable at x=0
- f(x) is discontinuous at x=0
Q. The approximate value of√(1.97)2(4.02)2(3.98)2
- 31.59
- 5.009
- 5.734
- 5.099
Q. Let f(x)={x3, x<0x2, x≥0 then
- f(x) is continuous at x=0
- f(x) is differentiable at x=0
- f′(x) is continuous on R
- f′′(x) exists for all x ϵ R
Q. If f(x)=min{x2, −x+1, sgn|−x|} then f(x) is
(where sgn(x) denotes signum function of x)
(where sgn(x) denotes signum function of x)
- continuous at x=0
- discontinuous at one point
- non-differentiable at 3 points
- differentiable at x=12
Q. If f(x)=min{x2, −x+1, sgn|−x|} then f(x) is
(where sgn(x) denotes signum function of x)
(where sgn(x) denotes signum function of x)
- continuous at x=0
- discontinuous at one point
- non-differentiable at 3 points
- differentiable at x=12
Q. If f(x)=⎧⎪
⎪⎨⎪
⎪⎩x−12x2−7x+5, x≠1−13, x=1 then f′(1) is equal to
- −(29)
- 13
- −13
- −(19)
Q. How do you simplify 843 ?
Q. The minimum value of α for which the equation 4sinx+11−sinx=α has at least one solution in (0, π2) is
Q. Consider the function f(x)=2√6−[x] at 2<x≤3 , where [x] denotes step up function, then at x=2 the function
- is continuous
- has missing point removable discontinuity
- has isolates missing point removable discontinuity
- has non removable discontinuity finite type
Q. Each of the following function is defined to be zero at x = 0
f1(x)=x2 sgn (x)
f2(x)=∫x0t2 sin (1t)dt
f3(x)=x−13 [sin x]
f4(x)=x3[−x]
[where sgn(x) denotes signum function and [.] denotes greatest integer function]
List - IList - IIIThe function f1(P)continuous but not differentiable at x = 0IIThe function f2 is (Q)first derivative exists at x = 0 but second derivative does not existIIIThe function f3 is(R)second derivative exists at x = 0, but it is not continuous thereIVThe function f4 is (S)second derivative exists at x = 0and is continuous at x = 0.
Which of the following is the only CORRECT combination?
f1(x)=x2 sgn (x)
f2(x)=∫x0t2 sin (1t)dt
f3(x)=x−13 [sin x]
f4(x)=x3[−x]
[where sgn(x) denotes signum function and [.] denotes greatest integer function]
List - IList - IIIThe function f1(P)continuous but not differentiable at x = 0IIThe function f2 is (Q)first derivative exists at x = 0 but second derivative does not existIIIThe function f3 is(R)second derivative exists at x = 0, but it is not continuous thereIVThe function f4 is (S)second derivative exists at x = 0and is continuous at x = 0.
Which of the following is the only CORRECT combination?
- (II), (Q)
- (III), (R)
- (IV), (S)
- (I), (P)
Q. Let f(x)={x3, x<0x2, x≥0 then
- f(x) is continuous at x=0
- f(x) is differentiable at x=0
- f′(x) is continuous on R
- f′′(x) exists for all x ϵ R
Q. Let f1(x)=x tan−1x, f2(x)={xln2;x≠11;x=1}, f3(x)=⎧⎨⎩(x+1) e(1|x|+1x), x≠00 , x=0⎫⎬⎭f4(x)=2tan(π4−x)cot 2x if x≠π4
List - IList - II(I) Number of critical points for f1(x)(P) -1 over its domain is(II) Derivative of f2(x) at x=1 is(Q) 0(III) Number of points of discountinuity(R) 1 forf3(x) in the interval [-2, 2]is(IV) Value of f4(π4) such that the(S) 2 function is continuos everywhere in the interval [π6, π3] is(T) 3(U) None of these
Which of the following is only CORRECT combination?
List - IList - II(I) Number of critical points for f1(x)(P) -1 over its domain is(II) Derivative of f2(x) at x=1 is(Q) 0(III) Number of points of discountinuity(R) 1 forf3(x) in the interval [-2, 2]is(IV) Value of f4(π4) such that the(S) 2 function is continuos everywhere in the interval [π6, π3] is(T) 3(U) None of these
Which of the following is only CORRECT combination?
- I→(S)
- II→(S)
- III→(R)
- IV→(Q)
Q. Let f1(x)=x tan−1x, f2(x)={xln2;x≠11;x=1}, f3(x)=⎧⎨⎩(x+1) e(1|x|+1x), x≠00 , x=0⎫⎬⎭f4(x)=2tan(π4−x)cot 2x if x≠π4
List - IList - II(I) Number of critical points for f1(x)(P) -1 over its domain is(II) Derivative of f2(x) at x=1 is(Q) 0(III) Number of points of discountinuity(R) 1 forf3(x) in the interval [-2, 2]is(IV) Value of f4(π4) such that the(S) 2 function is continuos everywhere in the interval [π6, π3] is(T) 3(U) None of these
Which of the following is only CORRECT combination?
List - IList - II(I) Number of critical points for f1(x)(P) -1 over its domain is(II) Derivative of f2(x) at x=1 is(Q) 0(III) Number of points of discountinuity(R) 1 forf3(x) in the interval [-2, 2]is(IV) Value of f4(π4) such that the(S) 2 function is continuos everywhere in the interval [π6, π3] is(T) 3(U) None of these
Which of the following is only CORRECT combination?
- I→(R)
- II→(T)
- III→(U)
- IV→(Q)
Q. Prove that ∫a−ax3√a2−x2dx=0