General Equation of Parabola
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What are the parts of a hyperbola?
The equation of the parabola whose focus is (1, -1) and the directrix is x+y+7=0 is
x2+y2−2xy−18x−10y=0
x2−18x−10y−45=0
x2+y2−18x−10y−45=0
x2+y2−2xy−18x−10y−45=0
The equation 16x2+y2+8xy−74x−78y+212=0 represents
a circle
a parabola
an ellipse
a hyperbola
- 1√10
- 1
- 1√5
- √5
Find the equation of the parabola whose focus is (5, 2) and having vertex at (3, 2).
Find the equation of the parabola whose:
(i) focus is (3, 0) and the directrix is 3x+4y=1
(ii) focus is (1, 1) and the directrix is x+y+1=0
(iii) focus is (0, 0) and the directrix is 2x-y-1=0
(iv) focus is (2, 3) and the directrix is x-4y+3=0
- Latus rectum is half the latus rectum of the original parabola
- Vertex is (a2, 0)
- Directrix is y−axis
- Focus has the co-ordinates (a, 0)
- (−p2, p)
- (p2, p)
- (p2, −p)
- (p2, −p2)
- x2=8(y+3)
- y2=8(x+3)
- x2=8(y−3)
- y2=8(x−3)
If the points (0, 4) and (0, 2) are respectively the vertex and focus of the parabola, then find the equation of the parabola.
Find the equation of the parabola whose focus is the point (2, 3) and directrix is the line x-4y+3=0.Also, find the length of its latus-rectum.
The equation of the parabola whose vertex is (a, 0) and the directrix has the equation x+y=3a, is
none of these
x2+y2+2xy+6ax+10ay+7a2=0
x2−2xy+y2+6ax+10ay−7a2=0
x2−2xy+y2−6ax+10ay−7a2=0
Write the equation of the parabola with focus (0, 0) and directrix x+y-4=0.
If and are three given points, then the locus of the point satisfying the relation , is
A straight line parallel to x-axis
A circle passing through the origin
A circle with the center at the origin
A straight line parallel to the y-axis
What is the focus of a parabola?
If the line y=mx+a meets the parabola y2=4ax at two points whose abscissas are x1 and x2, then x1+x2=0 if
- m=1
- m=2
- m=−12
- m=−1
- 4x2+9y2−156x−104y−12xy=0
- 9x2+4y2−104x−156y−12xy=0
- 9x2+4y2−156x−104y−12xy=0
- 9x2+4y2−104x+156y+12xy=0
If and are the parameters of the endpoints of a focal chord for the parabola , then which one is correct.
- Equation of axis of the parabola is 6x+8y−5=0
- Equation of tangent at vertex of the parabola is 6x+8y−5=0
- Length of latus rectum is 32 units
- Length of latus rectum is 6 units
- equation of the parabola is (4x−3y+2)2=100(3x+4y−11)
- equation of the parabola is (3x+4y−11)2=100(4x−3y+2)
- length of latus rectum of the parabola is 5 units
- length of latus rectum of the parabola is 20 units
The equation of the parabola with focus (0, 0) and directrix x+y=4 is
x2+y2−2xy+8x+8y−16=0
x2+y2−2xy+8x+8y=0
x2+y2+8x+8y−16=0
x2−y2+8x+8y−16=0
Write the equation of the parabola whose vertex is at (-3, 0) and the directrix is x+5=0
- 2ab
- ab
- a2+b22
- ab
- y=-3
- x=-3
- x=2
- none of these
- x2−3x−y=0
- x2+3x+y=0
- x2−4x−2y=0
- x2−4x−2y=0
- (x1)2=8(y−1)
- (y−1)2=8(x−3)
- (y−1)2=8(x−1)
- (x−3)2=8(y−1)
- SP≠ST=SN
- SP=ST≠SN
- SP≠ST≠SN
- SP=ST=SN