Logarithms
Trending Questions
Q. The value of (0.16)log2.5(13+132+⋯∞) is
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The solution set of the equation is
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The cube root of is
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The number of solutions of the equation is / are
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If the functions and are defined from the set of real numbers such that , and then is defined by
Q. The value of (3√log34−4√log43)2 is
Q. Integrate the function 1√8+3x−x2
Q. If x1 and x2 are two real solutions of the equation (x)lnx2=e18, then the product (x1.x2) equals
- (cot25∘)(cos25∘)cot25∘−cos25∘
- (tan210∘)(sin210∘)tan210∘−sin210∘
- sec0+secπ7+sec2π7+sec3π7+sec4π7+sec5π7+sec6π7=1
- √1−sin2110∘⋅sec110∘
Q. The natural number x, satisfying log10(x2−12x+36)=2 is
Q. Consider the equation (1+a+b)2=3(1+a2+b2), where a, b are real numbers. Then
- there are infinitely many solution pairs (a, b)
- there is no solution pair (a, b)
- there are exactly two solution pairs (a, b)
- there is exactly one solution pair (a, b)
Q. If x1 and x2 are two real solutions of the equation (x)lnx2=e18, then the product (x1.x2) equals
- (cot25∘)(cos25∘)cot25∘−cos25∘
- (tan210∘)(sin210∘)tan210∘−sin210∘
- sec0+secπ7+sec2π7+sec3π7+sec4π7+sec5π7+sec6π7=1
- √1−sin2110∘⋅sec110∘
Q. If ∫2x+3x2−5x+6dx=9ln(x−3)−7ln(x−2)+A, then A=
- 5 ln (x-2) +constant
- -4 ln (x-3)+constant
- Constant
- None of these
Q. The rationalising factor of 23√5 is _________.
- 3√52
- 53
- 52
- 3√5
Q. The value of (0.16)log2.5⎛⎝13+132+132+⋯to ∞⎞⎠ is equal to
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Integrate the function: 1√(x−1)(x−2)
Q. Integrate the rational function: x(x+1)(x+2)
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The set of real values of x satisfying the equation
|x−1|log3(x2)−2logx(9)=(x−1)7
is
{2}
{27, 81}
{81}
{2, 81}
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Let f:R→R be a differentiable function satisfying f(x+y3)=2+f(x)+f(y)3∀x, y∈R and f′(2)=2, then answer the following questions:
The range of g(x)=∣∣∣f∣∣∣x2∣∣∣∣∣∣ is- [1, ∞)
- [2, ∞)
- [0, ∞)
- None of these
Q. Let Sn(x)=loga1/2x+loga1/3x+loga1/6x+loga1/11x+loga1/18x+loga1/27x+⋯ up to n-terms, where a>1. If S24(x)=1093 and S12(2x)=265, then value of a is equal to
Q. If A is the solution set of the equation logx2⋅log2x2=log4x2 and B is the solution set of the equation xlogx(3−x)2=25, then n(A∪B) is equal to
- n(A×B)
- n(A−B)+n(B−A)
- n((A−B)×(B−A))
- n(A∪B)−n(A∩B)
Q. If log10a12=log10b21=log10c15, then bc is equal to
- a
- a2
- a3
- a4
Q.
C1+2C2+3C3+4C4+......+nCn =