Mean Deviation about Median
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The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.
Daily Pocket Allowance(in c) | |||||||
Number of children |
The number of telephone calls received at an exchange in 245 successive one-minute intervals are shown in the following frequency distribution :
Number of calls01234567Frequency1421254351403912
Compute the mean deviation about median.
If the mean deviation about the median of the numbers a, 2a, ......, 50a is 50, then |a| equals
3
4
5
2
- 4.2
- 2.4
- 3.4
- 4.3
The mean deviation from the median is
less than that measured from any other value.
equal to that measured from another values
maximum if all observations are positive
greater than that measured from any other value.
A class has 15 students whose ages are 14, 17, 15, 14, 21, 17, 19, 20, 16, 18, 20, 17, 16, 19, and 20yr. One student is selected in such a manner that each has the same chance of being of chosen and the age X of the selected student is recorded. What is the probability distribution of the random variable X? Find mean, variance and Standard Deviation (SD) of X.
The age distribution of 100 life insurance policy holders is as follows :
Age (on nearest birth day)17−19.520−25.526−35.536−40.541−50.551−55.556−60.561−70.5No. of persons5161226141265
Calculate the mean deviation from the median age.
Calculate the mean deviation about the median of the following frequency distribution :
xi57911131517fi246810128
Calculate the mean deviation about the median of the following observations :
(i) 3011, 2780, 3020, 2354, 3541, 4150, 5000
(ii) 38, 70, 48, 34, 42, 55, 63, 46, 54, 44
(iii) 34, 66, 30, 38, 44, 50, 40, 60, 42, 51
(iv) 22, 24, 30, 27, 29, 31, 25, 28, 41, 42
(v) 38, 70, 48, 34, 63, 42, 55, 44, 53, 47
Calculate the mean deviation of the following income groups of five and seven members from their medians :
IIIIncome in RsIncome in Rs400038004200400044004200460044004800460048005800
- x1
- x51
- x50+x512
- x1+x2+⋯+x101101
Find the value of x, y and z from the following equation:
(i) [43x5]=[yz15]
(ii) [x+y25+zxy]=[6258]
(iii) ⎡⎢⎣x+y+zx+zy+z⎤⎥⎦=⎡⎢⎣957⎤⎥⎦
Find the mean deviation from the median for the following data :
(i) xi1521273035fi35678
(ii) xi74894254919435fi201224534
(iii) Marks obtained1011121415No. of students23834
- 5.2
- 3.3
- 2.4
- 2
Calculate mean deviation about median age for the age distribution of 100 persons given below :
Age16−2021−2526−3031−3536−4041−4546−5051−55No. of persons5612142612169
[a−b2a+c2a−b3c+d]=[−15013]
Compute the mean deviation from the median of the following distribution :
Class0−1010−2020−3030−4040−50Frequency51020510
- 5.2
- 3.3
- 2
- 2.4
xi 5 7 9 10 12 15
fi 8 6 2 2 2 6
If the mean deviation about the median of the numbers a, 2a, ......, 50a is 50, then |a| equals
3
4
5
2
- 4
- 5
- 6
- 8
- 2
- 1
- 3
- c
- 2 units
- 4 units
- 8 units
- 2√29 units
- 15
- 1.5
- 42
- 35
- 3
- 2
- 3.75
- 2.57
- 12
- 10.5
- 11.5
- 11
- True
- False
- ∣∣∣ap∣∣∣σx
- paσx
- p2aσx
- ∣∣pa∣∣σx
- A.P.
- G.P.
- H.P.
- none
Calculate mean deviation about mean and median for given observations {1, 1, 4, 2, 6, 100, 150, 200, 400}
102.4, 93.55
102.4, 92.54
1024, 92.55
103.4, 93.55