Quadratic Equation
Trending Questions
- (12, 31]−{1}
- [−12, 1)
- [2, 3)
- (1, 52]
- −34
- 14
- 34
- −14
Let A = {1, 2, 3}, B = {1, 3, 5}. If relation R from A to B is given by
R = {(1, 3), (2, 5), (3, 3)}. Then, R−1 is
{(1, 3), (2, 5), (3, 3), }
{(1, 3), (5, 2)}
None of these
{(3, 3), (3, 1), (5, 2), }
Using identities, evaluate .
Let , f(x)=ax2+bx+c, g(x)=ax2+px+q where a, b, c, q, p, ϵ R and b ≠ p. If their discriminants are equal and f(x) = g(x) has a root , α then
will be G.M of all the roots of f(x) = 0, g(x) = 0
will be A.M. of the roots of f(x) = 0, g(x) = 0
will be A.M of the roots of f(x) = 0 or g(x) = 0
will be G.M of the roots of f(x) = 0 or g(x) = 0
(B) 5x2−8x=−3(7−2x)
If cos2 π8 is a root of equation x2 + ax + b = 0 where a, b ϵ Q then a + b =
−78
87
−12
2
- −174
- −153
- −134
- −113
If there is a term containing x2rin(x+1x2)n−3, then :
n-2r is a positive integral multiple of 3
n-2r is even
n-2r is odd
n = 2r
- −1
- −2
- 2
- 1
- (x+1)2=2(x−3)
- (x−2)(x+1)=(x−1)(x+3)
- x2−2x=(−2)(3−x)
- (x+2)(x−2)=−x2
- It is a constant polynomial
- It is a polynomial of degree 0
- It is a monomial
- The number of zeroes of the polynomial is 0
(D) x2+5x−5=(x−3)2
- π2
- π
- −3π2
- 3π2
Which of the following is an identity?
(x−2)2=x2−4x+4
x2−4x+4=0
(x+3)2=x2+5x+8
2x−1=0
If tan θ1, tan θ2, tan θ3 are the real roots of x3−(a+1)x2+(b−a)x−b=0 where θ1, θ2, θ3 are acute then θ1+θ2+θ3=
5π6
π2
6π5
π4
xa+yb=2; ax−by=a2−b2
- (x+1)2=2(x−3)
- (x−2)(x+1)=(x−1)(x+3)
- x2−2x=(−2)(3−x)
- (x+2)(x−2)=−x2
- x2−2=0
- (x + 2)2 = x2
- x2−5x=−6
- 5t2−√3t+7=√5
(E) 7x3−2x2+10=(2x−5)2
- 3
- 4
- 1
- 2
- The equation has exactly two solution
- The equation has more than two solutions
- The sum of all the solutions of the equation is 6
- The sum of all the solutions of the equation is 4
- θ=nπ
- θ=nπ+π4
- θ=nπ+tan−1(−2)
- θ=nπ+tan−1(2)
If a and b are the roots of equation x2 + 4x + p = 0 where P= ∑nr=0 ncr 1+rx(1+nx)r(−1)r
then the value of |a−b| is
2
6
None of these
4
- −34
- 14
- 34
- −14